2.1 Problem set

>>(6*7)+4^2-2^4 (ans = 42)

>>((3^2+2^3)/(4^5-5^4))+((sqrt(64)-5^2)/(4^5+5^6+7^8)) (ans = 0.0426)

>>log10(10^2)+10^5 (ans = 100002)

>>exp(2)+2^3-log(exp(2)) (ans = 13.3891)

>>sin(2*pi)+cos(pi/4) (ans = 0.7071)

>>tan(pi/3)+cos(270*pi/180)+sin(270*pi/180)+cos(pi/3) (ans = 1.2321)

>>A=[2 4; 1 5] A =2 4 1 5>>B=[1; 2] B =1 2>>Solution=A\B Solution =-0.5000 0.5000

>>p=[4 0 3 -1 0] p =4 0 3 -1 0>>polyval(p,5) ans =2570>>

First, we need to enter the data sets. Because it is rather a large table, using Variable Editor is more convenient. See the figures below:

Next, we will calculate the cross-sectional area. Area=pi/4*(0.0127^2) Area =1.2668e-004

Now, we can find the Stress values with the following, note that we are obtaining results in MPa: Sigma=(Load_N./Area)*10^(-6) Sigma =0 38.602277.1964 115.8065154.4086 193.0108218.0351 232.0076257.9792 268.0047272.9780 278.0302281.9773 320.0269381.9955 465.9888519.9844 548.0085549.9820 537.9830480.0403

For strain calculation, we will first find the change in length: Delta_L=Length_mm-50.800 Delta_L =0 0.01020.0203 0.03050.0406 0.05080.0610 0.07110.1016 0.12700.1524 0.17780.2032 1.01602.5400 5.08007.6200 10.160010.6680 12.700015.2400

Now we can determine Strain with the following: Epsilon=Delta_L./50.800 Epsilon =0 0.00020.0004 0.00060.0008 0.00100.0012 0.00140.0020 0.00250.0030 0.00350.0040 0.02000.0500 0.10000.1500 0.20000.2100 0.25000.3000

The final results can be tabulated as foolows: [Sigma Epsilon] ans =0 0 38.6022 0.000277.1964 0.0004 115.8065 0.0006154.4086 0.0008 193.0108 0.0010218.0351 0.0012 232.0076 0.0014257.9792 0.0020 268.0047 0.0025272.9780 0.0030 278.0302 0.0035281.9773 0.0040 320.0269 0.0200381.9955 0.0500 465.9888 0.1000519.9844 0.1500 548.0085 0.2000549.9820 0.2100 537.9830 0.2500480.0403 0.3000