<< Chapter < Page Chapter >> Page >

(See Exercise 19 from "Problems On Random Vectors and Joint Distributions"). f X Y ( t , u ) = 12 179 ( 3 t 2 + u ) , for 0 t 2 , 0 u min { 2 , 3 - t } .

f X ( t ) = I [ 0 , 1 ] ( t ) 24 179 ( 3 t 2 + 1 ) + I ( 1 , 2 ] ( t ) 6 179 ( 9 - 6 t + 19 t 2 - 6 t 3 )
f Y ( u ) = I [ 0 , 1 ] ( u ) 24 179 ( 4 + u ) + I ( 1 , 2 ] ( u ) 12 179 ( 27 - 24 u + 8 u 2 - u 3 )
E [ X ] = 2313 1790 , E [ Y ] = 778 895 , E [ X 2 ] = 1711 895 , E [ Y 2 ] = 916 895 , E [ X Y ] = 1811 1790
tuappr: [0 2] [0 2]400 400 (12/179)*(3*t.^2 + u).*(u<=min(2,3-t)) EX = 1.2923 EY = 0.8695 EX2 = 1.9119 EY2 = 1.0239 EXY = 1.0122
Got questions? Get instant answers now!

(See Exercise 20 from "Problems On Random Vectors and Joint Distributions"). f X Y ( t , u ) = 12 227 ( 3 t + 2 t u ) , for 0 t 2 , 0 u min { 1 + t , 2 } .

f X ( t ) = I [ 0 , 1 ] ( t ) 12 227 ( t 3 + 5 t 2 + 4 t ) + I ( 1 , 2 ] ( t ) 120 227 t
f Y ( u ) = I [ 0 , 1 ] ( u ) 24 227 ( 2 u + 3 ) + I ( 1 , 2 ] ( u ) 6 227 ( 2 u + 3 ) ( 3 + 2 u - u 2 )
= I [ 0 , 1 ] ( u ) 24 227 ( 2 u + 3 ) + I ( 1 , 2 ] ( u ) 6 227 ( 9 + 12 u + u 2 - 2 u 3 )
E [ X ] = 1567 1135 , E [ Y ] = 2491 2270 , E [ X 2 ] = 476 227 , E [ Y 2 ] = 1716 1135 , E [ X Y ] = 5261 3405
tuappr: [0 2] [0 2]400 400 (12/227)*(3*t + 2*t.*u).*(u<=min(1+t,2)) EX = 1.3805 EY = 1.0974 EX2 = 2.0967 EY2 = 1.5120 EXY = 1.5450
Got questions? Get instant answers now!

(See Exercise 21 from "Problems On Random Vectors and Joint Distributions"). f X Y ( t , u ) = 2 13 ( t + 2 u ) , for 0 t 2 , 0 u min { 2 t , 3 - t } .

f X ( t ) = I [ 0 , 1 ] ( t ) 12 13 t 2 + I ( 1 , 2 ] ( t ) 6 13 ( 3 - t )
f Y ( u ) = I [ 0 , 1 ] ( u ) ( 4 13 + 8 13 u - 9 52 u 2 ) + I ( 1 , 2 ] ( u ) ( 9 13 + 6 13 u - 21 52 u 2 )
E [ X ] = 16 13 , E [ Y ] = 11 12 , E [ X 2 ] = 219 130 , E [ Y 2 ] = 83 78 , E [ X Y ] = 431 390
tuappr: [0 2] [0 2]400 400 (2/13)*(t + 2*u).*(u<=min(2*t,3-t)) EX = 1.2309 EY = 0.9169 EX2 = 1.6849 EY2 = 1.0647 EXY = 1.1056
Got questions? Get instant answers now!

(See Exercise 22 from "Problems On Random Vectors and Joint Distributions"). f X Y ( t , u ) = I [ 0 , 1 ] ( t ) 3 8 ( t 2 + 2 u ) + I ( 1 , 2 ] ( t ) 9 14 t 2 u 2 ,

                                     for 0 u 1 .

f X ( t ) = I [ 0 , 1 ] ( t ) 3 8 ( t 2 + 1 ) + I ( 1 , 2 ] ( t ) 3 14 t 2 , f Y ( u ) = 1 8 + 3 4 u + 3 2 u 2 0 u 1
E [ X ] = 243 224 , E [ Y ] = 11 16 , E [ X 2 ] = 107 70 , E [ Y 2 ] = 127 240 , E [ X Y ] = 347 448
tuappr [0 2] [0 1]400 200 (3/8)*(t.^2+2*u).*(t<=1) + (9/14)*(t.^2.*u.^2).*(t>1) EX = 1.0848 EY = 0.6875 EX2 = 1.5286 EY2 = 0.5292 EXY = 0.7745
Got questions? Get instant answers now!

The class { X , Y , Z } of random variables is iid (independent, identically distributed) with common distribution

X = [ - 5 - 1 3 4 7 ] P X = 0 . 01 * [ 15 20 30 25 10 ]

Let W = 3 X - 4 Y + 2 Z . Determine E [ W ] . Do this using icalc, then repeat with icalc3 and compare results.

Use x and p x to prevent renaming.

x = [-5 -1 3 4 7];px = 0.01*[15 20 30 25 10];icalc Enter row matrix of X-values xEnter row matrix of Y-values x Enter X probabilities pxEnter Y probabilities px Use array operations on matrices X, Y, PX, PY, t, u, and PG = 3*t -4*u; [R,PR]= csort(G,P); icalcEnter row matrix of X-values R Enter row matrix of Y-values xEnter X probabilities PR Enter Y probabilities pxUse array operations on matrices X, Y, PX, PY, t, u, and P H = t + 2*u;EH = total(H.*P) EH = 1.6500[W,PW] = csort(H,P); % AlternateEW = W*PW' EW = 1.6500icalc3 % Solution with icalc3 Enter row matrix of X-values xEnter row matrix of Y-values x Enter row matrix of Z-values xEnter X probabilities px Enter Y probabilities pxEnter Z probabilities px Use array operations on matrices X, Y, Z,PX, PY, PZ, t, u, v, and P K = 3*t - 4*u + 2*v;EK = total(K.*P) EK = 1.6500
Got questions? Get instant answers now!

(See Exercise 5 from "Problems on Functions of Random Variables") The cultural committee of a student organization has arranged a special deal for tickets to a concert. The agreement is that the organization will purchase tentickets at $20 each (regardless of the number of individual buyers). Additional tickets are available according to the following schedule:

11-20, $18 each; 21-30 $16 each; 31-50, $15 each; 51-100, $13 each

If the number of purchasers is a random variable X , the total cost (in dollars) is a random quantity Z = g ( X ) described by

g ( X ) = 200 + 18 I M 1 ( X ) ( X - 10 ) + ( 16 - 18 ) I M 2 ( X ) ( X - 20 ) +
( 15 - 16 ) I M 3 ( X ) ( X - 30 ) + ( 13 - 15 ) I M 4 ( X ) ( X - 50 )
where M 1 = [ 10 , ) , M 2 = [ 20 , ) , M 3 = [ 30 , ) , M 4 = [ 50 , )

Suppose X Poisson (75). Approximate the Poisson distribution by truncating at 150. Determine E [ Z ] and E [ Z 2 ] .

X = 0:150; PX = ipoisson(75,X);G = 200 + 18*(X - 10).*(X>=10) + (16 - 18)*(X - 20).*(X>=20) + ... (15 - 16)*(X- 30).*(X>=30) + (13 - 15)*(X - 50).*(X>=50); [Z,PZ]= csort(G,PX); EZ = Z*PZ'EZ = 1.1650e+03 EZ2 = (Z.^2)*PZ'EZ2 = 1.3699e+06
Got questions? Get instant answers now!

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
khuthadzo hii
Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
please help me with vectors in two dimensions
Mulaudzi Reply
how to calculate normal force
Mulaudzi
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Applied probability' conversation and receive update notifications?

Ask