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(See Exercise 19 from "Problems on Distribution and Density Functions"). The number of noise pulses arriving on a power circuit in an hour is a randomquantity having Poisson (7) distribution. What is the expected number of pulses in an hour?

X Poisson (7). E [ X ] = 7 .

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(See Exercise 24 and Exercise 25 from "Problems on Distribution and Density Functions"). The total operating time for the units in Exercise 24 is a random variable T gamma (20, 0.0002). What is the expected operating time?

X gamma (20, 0.0002). E [ X ] = 20 / 0 . 0002 = 100 , 000 .

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(See Exercise 41 from "Problems on Distribution and Density Functions"). Random variable X has density function

f X ( t ) = ( 6 / 5 ) t 2 for 0 t 1 ( 6 / 5 ) ( 2 - t ) for 1 < t 2 = I [ 0 , 1 ] ( t ) 6 5 t 2 + I ( 1 , 2 ] ( t ) 6 5 ( 2 - t )

What is the expected value E [ X ] ?

E [ X ] = t f X ( t ) d t = 6 5 0 1 t 3 d t + 6 5 1 2 ( 2 t - t 2 ) d t = 11 10
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Truncated exponential. Suppose X exponential ( λ ) and Y = I [ 0 , a ] ( X ) X + I ( a , ) ( X ) a .

  1. Use the fact that
    0 t e - λ t d t = 1 λ 2 and a t e - λ t d t = 1 λ 2 e - λ a ( 1 + λ a )
    to determine an expression for E [ Y ] .
  2. Use the approximation method, with λ = 1 / 50 , a = 30 . Approximate the exponential at 10,000 points for 0 t 1000 . Compare the approximate result with the theoretical result of part (a).
E [ Y ] = g ( t ) f X ( t ) d t = 0 a t λ e - λ t d t + a P ( X > a ) =
λ λ 2 [ 1 - e - λ a ( 1 + λ a ) ] + a e - λ a = 1 λ ( 1 - e - λ a )
tappr Enter matrix [a b]of x-range endpoints [0 1000] Enter number of x approximation points 10000Enter density as a function of t (1/50)*exp(-t/50) Use row matrices X and PX as in the simple caseG = X.*(X<=30) + 30*(X>30); EZ = G8PX'EZ = 22.5594 ez = 50*(1 - exp(-30/50)) % Theoretical valueez = 22.5594
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(See Exercise 1 from "Problems On Random Vectors and Joint Distributions", m-file npr08_01.m ). Two cards are selected at random, without replacement, from a standarddeck. Let X be the number of aces and Y be the number of spades. Under the usual assumptions, determine the joint distribution. Determine E [ X ] , E [ Y ] , E [ X 2 ] , E [ Y 2 ] , and E [ X Y ] .

npr08_01 Data in Pn, P, X, Y jcalcEnter JOINT PROBABILITIES (as on the plane) P Enter row matrix of VALUES of X XEnter row matrix of VALUES of Y Y Use array operations on matrices X, Y, PX, PY, t, u, and PEX = X*PX' EX = 0.1538ex = total(t.*P) % Alternateex = 0.1538 EY = Y*PY'EY = 0.5000 EX2 = (X.^2)*PX'EX2 = 0.1629 EY2 = (Y.^2)*PY'EY2 = 0.6176 EXY = total(t.*u.*P)EXY = 0.0769
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(See Exercise 2 from "Problems On Random Vectors and Joint Distributions", m-file npr08_02.m ). Two positions for campus jobs are open. Two sophomores, three juniors,and three seniors apply. It is decided to select two at random (each possible pair equally likely). Let X be the number of sophomores and Y be the number of juniors who are selected. Determine the joint distribution for { X , Y } and E [ X ] , E [ Y ] , E [ X 2 ] , E [ Y 2 ] , and E [ X Y ] .

npr08_02 Data are in X, Y,Pn, P jcalc- - - - - - - - - - - - EX = X*PX'EX = 0.5000 EY = Y*PY'EY = 0.7500 EX2 = (X.^2)*PX'EX2 = 0.5714 EY2 = (Y.^2)*PY'EY2 = 0.9643 EXY = total(t.*u.*P)EXY = 0.2143
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(See Exercise 3 from "Problems On Random Vectors and Joint Distributions", m-file npr08_03.m ). A die is rolled. Let X be the number of spots that turn up.A coin is flipped X times. Let Y be the number of heads that turn up. Determine the joint distribution for the pair { X , Y } . Assume P ( X = k ) = 1 / 6 for 1 k 6 and for each k , P ( Y = j | X = k ) has the binomial ( k , 1 / 2 ) distribution. Arrange the joint matrix as on the plane, with values of Y increasing upward. Determine the expected value E [ Y ] .

npr08_03 Answers are in X, Y, P, PY jcalc- - - - - - - - - - - - EX = X*PX'EX = 3.5000 EY = Y*PY'EY = 1.7500 EX2 = (X.^2)*PX'EX2 = 15.1667 EY2 = (Y.^2)*PY'EY2 = 4.6667 EXY = total(t.*u.*P)EXY = 7.5833
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Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
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