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This method can be time consuming and inexact. We shall now look at how to solve these problems algebraically.

Solution using cast diagrams

The sign of the trigonometric function

The first step to finding the trigonometry of any angle is to determine the sign of the ratio for a given angle. We shall do this for the sine function first and then do the same for the cosine and tangent.

The graph and unit circle showing the sign of the sine function.

In [link] we have split the sine graph into four quadrants , each 90 wide. We call them quadrants because they correspond to the four quadrants of the unit circle. We notice from [link] that the sine graph is positive in the 1 st and 2 nd quadrants and negative in the 3 rd and 4 th . [link] shows similar graphs for cosine and tangent.

Graphs showing the sign of the cosine and tangent functions.

All of this can be summed up in two ways. [link] shows which trigonometric functions are positive and which are negative in each quadrant.

The signs of the three basic trigonometric functions in each quadrant.
1 st 2 nd 3 rd 4 th
sin +VE +VE -VE -VE
cos +VE -VE -VE +VE
tan +VE -VE +VE -VE

A more convenient way of writing this is to note that all functions are positive in the 1 st quadrant, only sine is positive in the 2 nd , only tangent in the 3 rd and only cosine in the 4 th . We express this using the CAST diagram ( [link] ). This diagram is known as a CAST diagram as the letters, taken anticlockwise from the bottom right, read C-A-S-T. The letter in each quadrant tells us which trigonometric functions are positive in that quadrant. The `A' in the 1 st quadrant stands for all (meaning sine, cosine and tangent are all positive in this quadrant). `S', `C' and `T' ,of course, stand for sine, cosine and tangent. The diagram is shown in two forms. The version on the left shows the CAST diagram including the unit circle. This version is useful for equations which lie in large or negative ranges. The simpler version on the right is useful for ranges between 0 and 360 . Another useful diagram shown in [link] gives the formulae to use in each quadrant when solving a trigonometric equation.

The two forms of the CAST diagram and the formulae in each quadrant.

Magnitude of the trigonometric functions

Now that we know in which quadrants our solutions lie, we need to know which angles in these quadrants satisfy our equation.

Calculators give us the smallest possible answer (sometimes negative) which satisfies the equation. For example, if we wish to solve sin θ = 0 , 3 we can apply the inverse sine function to both sides of the equation to find:

θ = arcsin 0 , 3 = 17 , 46

However, we know that this is just one of infinitely many possible answers. We get the rest of the answers by finding relationships between this small angle, θ , and answers in other quadrants. To do this we use our small angle θ as a reference angle . We then look at the sign of the trigonometric function in order to decide in which quadrants we need to work (using the CAST diagram) and add multiples of the period to each, remembering that sine, cosine and tangent are periodic (repeating) functions. To add multiples of the period we use 360 · n (where n is an integer) for sine and cosine and 180 · n , n Z , for the tangent.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Math 1508 (lecture) readings in precalculus. OpenStax CNX. Aug 24, 2011 Download for free at http://cnx.org/content/col11354/1.1
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