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By the end of this section, you will be able to:
  • Simplify expressions using the Quotient Property of Exponents
  • Simplify expressions with zero exponents
  • Simplify expressions using the Quotient to a Power Property
  • Simplify expressions by applying several properties
  • Divide monomials

Before you get started, take this readiness quiz.

  1. Simplify: 8 24 .
    If you missed the problem, review Multiply and Divide Fractions .
  2. Simplify: ( 2 m 3 ) 5 .
    If you missed the problem, review Use Multiplication Properties of Exponents .
  3. Simplify: 12 x 12 y .
    If you missed the problem, review Multiply and Divide Fractions .

Simplify expressions using the quotient property of exponents

Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize these properties here.

Summary of exponent properties for multiplication

If a , b are real numbers and m , n are whole numbers, then

Product Property a m a n = a m + n Power Property ( a m ) n = a m n Product to a Power ( a b ) m = a m b m

Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. In Fractions you learned that fractions may be simplified by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property . This property will also help us work with algebraic fractions—which are also quotients.

Equivalent fractions property

If a , b , c are whole numbers where b 0 , c 0 , then

a b = a · c b · c and a · c b · c = a b

As before, we'll try to discover a property by looking at some examples.

Consider x 5 x 2 and x 2 x 3 What do they mean? x x x x x x x x x x x x Use the Equivalent Fractions Property. x x x x x x x 1 x x 1 x x x Simplify. x 3 1 x

Notice that in each case the bases were the same and we subtracted the exponents.

  • When the larger exponent was in the numerator, we were left with factors in the numerator and 1 in the denominator, which we simplified.
  • When the larger exponent was in the denominator, we were left with factors in the denominator, and 1 in the numerator, which could not be simplified.

We write:

x 5 x 2 x 2 x 3 x 5 2 1 x 3 2 x 3 1 x

Quotient property of exponents

If a is a real number, a 0 , and m , n are whole numbers, then

a m a n = a m n , m > n and a m a n = 1 a n m , n > m

A couple of examples with numbers may help to verify this property.

3 4 3 2 = ? 3 4 2 5 2 5 3 = ? 1 5 3 2 81 9 = ? 3 2 25 125 = ? 1 5 1 9 = 9 1 5 = 1 5

When we work with numbers and the exponent is less than or equal to 3 , we will apply the exponent. When the exponent is greater than 3 , we leave the answer in exponential form.

Simplify:

  1. x 10 x 8
  2. 2 9 2 2

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

Since 10>8, there are more factors of x in the numerator. x 10 x 8
Use the quotient property with m > n , a m a n = a m n . .
Simplify. x 2
Since 9>2, there are more factors of 2 in the numerator. 2 9 2 2
Use the quotient property with m > n , a m a n = a m n . .
Simplify. 2 7

Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.

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Simplify:

  1. x 12 x 9
  2. 7 14 7 5

  1. x 3
  2. 7 9

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Simplify:

  1. y 23 y 17
  2. 8 15 8 7

  1. y 6
  2. 8 8

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Simplify:

  1. b 10 b 15
  2. 3 3 3 5

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

Since 15>10, there are more factors of b in the denominator. b 10 b 15
Use the quotient property with n > m , a m a n = 1 a n m . .
Simplify. 1 b 5
Since 5>3, there are more factors of 3 in the denominator. 3 3 3 5
Use the quotient property with n > m , a m a n = 1 a n m . .
Simplify. 1 3 2
Apply the exponent. 1 9

Notice that when the larger exponent is in the denominator, we are left with factors in the denominator and 1 in the numerator.

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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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