This module is from Fundamentals of Mathematics by Denny Burzynski and Wade Ellis, Jr. This module discusses division of fractions. By the end of the module students should be able to determine the reciprocal of a number and divide one fraction by another.
Section overview
Reciprocals
Dividing Fractions
Reciprocals
Reciprocals Two numbers whose product is 1 are called
reciprocals of each other.
Sample set a
The following pairs of numbers are reciprocals.
3
4
and
4
3
︸
3
4
⋅
4
3
=
1
7
16
and
16
7
︸
7
16
⋅
16
7
=
1
1
6
and
6
1
︸
1
6
⋅
6
1
=
1
Notice that we can find the reciprocal of a nonzero number in fractional form by inverting it (exchanging positions of the numerator and denominator).
Practice set a
Find the reciprocal of each number.
3
10
size 12{ { {3} over {"10"} } } {}
10
3
size 12{ { {"10"} over {3} } } {}
2
3
size 12{ { {2} over {3} } } {}
3
2
size 12{ { {3} over {2} } } {}
7
8
size 12{ { {7} over {8} } } {}
8
7
size 12{ { {8} over {7} } } {}
1
5
size 12{ { {1} over {5} } } {}
2
2
7
size 12{2 { {2} over {7} } } {}
Hint Write this number as an improper fraction first.
7
16
size 12{ { {7} over {"16"} } } {}
5
1
4
size 12{5 { {1} over {4} } } {}
4
21
size 12{ { {4} over {"21"} } } {}
10
3
16
size 12{"10" { {3} over {"16"} } } {}
16
163
size 12{ { {"16"} over {"163"} } } {}
Dividing fractions
Our concept of division is that it indicates
how many times one quantity is contained in another quantity. For example, using the diagram we can see that there are 6 one-thirds in 2.
There are 6 one-thirds in 2.
Since 2 contains six
1
3
size 12{ { {1} over {3} } } {} 's we express this as
Using these observations, we can suggest the following method for dividing a number by a fraction.
Dividing one fraction by another fraction To divide a first fraction by a second, nonzero fraction, multiply the first traction by the reciprocal of the second fraction.
Invert and multiply This method is commonly referred to as
"invert the divisor and
multiply."
Sample set b
Perform the following divisions.
1
3
÷
3
4
size 12{ { {1} over {3} } div { {3} over {4} } } {} . The divisor is
3
4
size 12{ { {3} over {4} } } {} . Its reciprocal is
4
3
size 12{ { {4} over {3} } } {} . Multiply
1
3
size 12{ { {1} over {3} } } {} by
4
3
size 12{ { {4} over {3} } } {} .
1
3
⋅
4
3
=
1
⋅
4
3
⋅
3
=
4
9
size 12{ { {1} over {3} } cdot { {4} over {3} } = { {1 cdot 4} over {3 cdot 3} } = { {4} over {9} } } {}
1
3
÷
3
4
=
4
9
size 12{ { {1} over {3} } div { {3} over {4} } = { {4} over {9} } } {}
3
8
÷
5
4
size 12{ { {3} over {8} } div { {5} over {4} } } {} The divisor is
5
4
size 12{ { {5} over {4} } } {} . Its reciprocal is
4
5
size 12{ { {4} over {5} } } {} . Multiply
3
8
size 12{ { {3} over {8} } } {} by
4
5
size 12{ { {4} over {5} } } {} .
3
3
2
⋅
4
1
5
=
3
⋅
1
2
⋅
5
=
3
10
size 12{ { {3} over { { { {3}}} cSub { size 8{2} } } } cdot { { { { {4}}} cSup { size 8{1} } } over {5} } = { {3 cdot 1} over {2 cdot 5} } = { {3} over {"10"} } } {}
3
8
÷
5
4
=
3
10
size 12{ { {3} over {8} } div { {5} over {4} } = { {3} over {"10"} } } {}
5
6
÷
5
12
size 12{ { {5} over {6} } div { {5} over {"12"} } } {} . The divisor is
5
12
size 12{ { {5} over {"12"} } } {} . Its reciprocal is
12
5
size 12{ { {"12"} over {5} } } {} . Multiply
5
6
size 12{ { {5} over {6} } } {} by
12
5
size 12{ { {"12"} over {5} } } {} .
5
1
6
1
⋅
12
2
5
1
=
1
⋅
2
1
⋅
1
=
2
1
=
2
size 12{ { { { { {5}}} cSup { size 8{1} } } over { { { {6}}} cSub { size 8{1} } } } cdot { { {"12"} cSup { size 8{2} } } over { {5} cSub { size 8{1} } } } = { {1 cdot 2} over {1 cdot 1} } = { {2} over {1} } =2} {}
5
6
÷
5
12
=
2
2
2
9
÷
3
1
3
size 12{2 { {2} over {9} } div 3 { {1} over {3} } } {} . Convert each mixed number to an improper fraction.
2
2
9
=
9
⋅
2
+
2
9
=
20
9
size 12{2 { {2} over {9} } = { {9 cdot 2+2} over {9} } = { {"20"} over {9} } } {} .
3
1
3
=
3
⋅
3
+
1
3
=
10
3
size 12{3 { {1} over {3} } = { {3 cdot 3+1} over {3} } = { {10} over {3} } } {} .
20
9
÷
10
3
size 12{ { {"20"} over {9} } div { {"10"} over {3} } } {} The divisor is
10
3
size 12{ { {"10"} over {3} } } {} . Its reciprocal is
3
10
size 12{ { {3} over {"10"} } } {} . Multiply
20
9
size 12{ { {"20"} over {9} } } {} by
3
10
size 12{ { {3} over {"10"} } } {} .
20
2
9
3
⋅
3
1
10
1
=
2
⋅
1
3
⋅
1
=
2
3
size 12{ { { { { {2}} { {0}}} cSup { size 8{2} } } over { { { {9}}} cSub { size 8{3} } } } cdot { { { { {3}}} cSup { size 8{1} } } over { { { {1}} { {0}}} cSub { size 8{1} } } } = { {2 cdot 1} over {3 cdot 1} } = { {2} over {3} } } {}
2
2
9
÷
3
1
3
=
2
3
size 12{2 { {2} over {9} } div 3 { {1} over {3} } = { {2} over {3} } } {}
12
11
÷
8
size 12{ { {"12"} over {"11"} } div 8} {} . First conveniently write 8 as
8
1
size 12{ { {8} over {1} } } {} .
12
11
÷
8
1
size 12{ { {"12"} over {"11"} } div { {8} over {1} } } {} The divisor is
8
1
size 12{ { {8} over {1} } } {} . Its reciprocal is
1
8
size 12{ { {1} over {8} } } {} . Multiply
12
11
size 12{ { {"12"} over {"11"} } } {} by
1
8
size 12{ { {1} over {8} } } {} .
12
3
11
⋅
1
8
2
=
3
⋅
1
11
⋅
2
=
3
22
size 12{ { { { { {1}} { {2}}} cSup { size 8{3} } } over {"11"} } cdot { {1} over { { { {8}}} cSub { size 8{2} } } } = { {3 cdot 1} over {"11" cdot 2} } = { {3} over {"22"} } } {}
12
11
÷
8
=
3
22
size 12{ { {"12"} over {"11"} } div 8= { {3} over {"22"} } } {}
7
8
÷
21
20
⋅
3
35
size 12{ { {7} over {8} } div { {"21"} over {"20"} } cdot { {3} over {"35"} } } {} . The divisor is
21
20
size 12{ { {"21"} over {"20"} } } {} . Its reciprocal is
20
21
size 12{ { {"20"} over {"21"} } } {} .
7
1
8
2
⋅
20
5
1
21
3
1
3
1
35
7
=
1
⋅
1
⋅
1
2
⋅
1
⋅
7
=
1
14
size 12{ { { {7} cSup { size 8{1} } } over { {8} cSub { size 8{2} } } } cdot { { {"20"} cSup { size 8{ {5} cSup { size 6{1} } } } } over { {"21"} cSub { {3} cSub { size 6{1} } } } } size 12{ cdot { { {3} cSup {1} } over { size 12{ {"35"} cSub {7} } } } } size 12{ {}= { {1 cdot 1 cdot 1} over {2 cdot 1 cdot 7} } = { {1} over {"14"} } }} {}
7
8
÷
21
20
⋅
3
25
=
1
14
size 12{ { {7} over {8} } div { {"21"} over {"20"} } cdot { {3} over {"25"} } = { {1} over {"14"} } } {}
How many
2
3
8
size 12{2 { {3} over {8} } } {} -inch-wide packages can be placed in a box 19 inches wide?
The problem is to determine how many two and three eighths are contained in 19, that is, what is
19
÷
2
3
8
size 12{"19" div 2 { {3} over {8} } } {} ?
2
3
8
=
19
8
size 12{2 { {3} over {8} } = { {"19"} over {8} } } {} Convert the divisor
2
3
8
size 12{2 { {3} over {8} } } {} to an improper fraction.
19
=
19
1
size 12{"19"= { {"19"} over {1} } } {} Write the dividend 19 as
19
1
size 12{ { {"19"} over {1} } } {} .
19
1
÷
19
8
size 12{ { {"19"} over {1} } div { {"19"} over {8} } } {} The divisor is
19
8
size 12{ { {"19"} over {8} } } {} . Its reciprocal is
8
19
size 12{ { {8} over {"19"} } } {} .
19
1
1
⋅
8
19
1
=
1
⋅
8
1
⋅
1
=
8
1
=
8
size 12{ { { {"19"} cSup { size 8{1} } } over {1} } cdot { {8} over { {"19"} cSub { size 8{1} } } } = { {1 cdot 8} over {1 cdot 1} } = { {8} over {1} } =8} {}
Thus, 8 packages will fit into the box.
Practice set b
Perform the following divisions.
1
2
÷
9
8
size 12{ { {1} over {2} } div { {9} over {8} } } {}
4
9
size 12{ { {4} over {9} } } {}
3
8
÷
9
24
size 12{ { {3} over {8} } div { {9} over {"24"} } } {}
7
15
÷
14
15
size 12{ { {7} over {"15"} } div { {"14"} over {"15"} } } {}
1
2
size 12{ { {1} over {2} } } {}
8
÷
8
15
size 12{8 div { {8} over {"15"} } } {}
6
1
4
÷
5
12
size 12{6 { {1} over {4} } div { {5} over {"12"} } } {}
3
1
3
÷
1
2
3
size 12{3 { {1} over {3} } div 1 { {2} over {3} } } {}
5
6
÷
2
3
⋅
8
25
size 12{ { {5} over {6} } div { {2} over {3} } cdot { {8} over {"25"} } } {}
2
5
size 12{ { {2} over {5} } } {}
A container will hold 106 ounces of grape juice. How many
6
5
8
size 12{6 { {5} over {8} } } {} -ounce glasses of grape juice can be served from this container?
Determine each of the following quotients and then write a rule for this type of division.
1
÷
2
3
size 12{1 div { {2} over {3} } } {}
3
2
size 12{ { {3} over {2} } } {}
1
÷
3
8
size 12{1 div { {3} over {8} } } {}
8
3
size 12{ { {8} over {3} } } {}
1
÷
3
4
size 12{1 div { {3} over {4} } } {}
4
3
size 12{ { {4} over {3} } } {}
1
÷
5
2
size 12{1 div { {5} over {2} } } {}
2
5
size 12{ { {2} over {5} } } {}
When dividing 1 by a fraction, the quotient is the
.
is the reciprocal of the fraction.
Exercises
For the following problems, find the reciprocal of each number.
4
5
size 12{ { {4} over {5} } } {}
5
4
size 12{ { {5} over {4} } } {} or
1
1
4
size 12{1 { {1} over {4} } } {}
8
11
size 12{ { {8} over {"11"} } } {}
2
9
size 12{ { {2} over {9} } } {}
9
2
size 12{ { {9} over {2} } } {} or
4
1
2
size 12{4 { {1} over {2} } } {}
1
5
size 12{ { {1} over {5} } } {}
3
1
4
size 12{3 { {1} over {4} } } {}
4
13
size 12{ { {4} over {"13"} } } {}
8
1
4
size 12{8 { {1} over {4} } } {}
3
2
7
size 12{3 { {2} over {7} } } {}
7
23
size 12{ { {7} over {"23"} } } {}
5
3
4
size 12{5 { {3} over {4} } } {}
For the following problems, find each value.
3
8
÷
3
5
size 12{ { {3} over {8} } div { {3} over {5} } } {}
5
8
size 12{ { {5} over {8} } } {}
5
9
÷
5
6
size 12{ { {5} over {9} } div { {5} over {6} } } {}
9
16
÷
15
8
size 12{ { {9} over {"16"} } div { {"15"} over {8} } } {}
3
10
size 12{ { {3} over {"10"} } } {}
4
9
÷
6
15
size 12{ { {4} over {9} } div { {6} over {"15"} } } {}
25
49
÷
4
9
size 12{ { {"25"} over {"49"} } div { {4} over {9} } } {}
225
196
size 12{ { {"225"} over {"196"} } } {} or
1
29
196
size 12{1 { {"29"} over {"196"} } } {}
15
4
÷
27
8
size 12{ { {"15"} over {4} } div { {"27"} over {8} } } {}
24
75
÷
8
15
size 12{ { {"24"} over {"75"} } div { {8} over {"15"} } } {}
3
5
size 12{ { {3} over {5} } } {}
5
7
÷
0
size 12{ { {5} over {7} } div 0} {}
7
8
÷
7
8
size 12{ { {7} over {8} } div { {7} over {8} } } {}
0
÷
3
5
size 12{0 div { {3} over {5} } } {}
4
11
÷
4
11
size 12{ { {4} over {"11"} } div { {4} over {"11"} } } {}
2
3
÷
2
3
size 12{ { {2} over {3} } div { {2} over {3} } } {}
7
10
÷
10
7
size 12{ { {7} over {"10"} } div { {"10"} over {7} } } {}
49
100
size 12{ { {"49"} over {"100"} } } {}
3
4
÷
6
size 12{ { {3} over {4} } div 6} {}
9
5
÷
3
size 12{ { {9} over {5} } div 3} {}
3
5
size 12{ { {3} over {5} } } {}
4
1
6
÷
3
1
3
size 12{4 { {1} over {6} } div 3 { {1} over {3} } } {}
7
1
7
÷
8
1
3
size 12{7 { {1} over {7} } div 8 { {1} over {3} } } {}
6
7
size 12{ { {6} over {7} } } {}
1
1
2
÷
1
1
5
size 12{1 { {1} over {2} } div 1 { {1} over {5} } } {}
3
2
5
÷
6
25
size 12{3 { {2} over {5} } div { {6} over {"25"} } } {}
85
6
size 12{ { {"85"} over {6} } } {} or
14
1
6
size 12{"14" { {1} over {6} } } {}
5
1
6
÷
31
6
size 12{5 { {1} over {6} } div { {"31"} over {6} } } {}
35
6
÷
3
3
4
size 12{ { {"35"} over {6} } div 3 { {3} over {4} } } {}
28
18
=
14
9
size 12{ { {"28"} over {"18"} } = { {"14"} over {9} } } {} or
1
5
9
size 12{1 { {5} over {9} } } {}
5
1
9
÷
1
18
size 12{5 { {1} over {9} } div { {1} over {"18"} } } {}
8
3
4
÷
7
8
size 12{8 { {3} over {4} } div { {7} over {8} } } {}
12
8
÷
1
1
2
size 12{ { {"12"} over {8} } div 1 { {1} over {2} } } {}
3
1
8
÷
15
16
size 12{3 { {1} over {8} } div { {"15"} over {"16"} } } {}
10
3
size 12{ { {"10"} over {3} } } {} or
3
1
3
size 12{3 { {1} over {3} } } {}
11
11
12
÷
9
5
8
size 12{"11" { {"11"} over {"12"} } div 9 { {5} over {8} } } {}
2
2
9
÷
11
2
3
size 12{2 { {2} over {9} } div "11" { {2} over {3} } } {}
4
21
size 12{ { {4} over {"21"} } } {}
16
3
÷
6
2
5
size 12{ { {"16"} over {3} } div 6 { {2} over {5} } } {}
4
3
25
÷
2
56
75
size 12{4 { {3} over {"25"} } div 2 { {"56"} over {"75"} } } {}
3
2
size 12{ { {3} over {2} } } {} or
1
1
2
size 12{1 { {1} over {2} } } {}
1
1000
÷
1
100
size 12{ { {1} over {"1000"} } div { {1} over {"100"} } } {}
3
8
÷
9
16
⋅
6
5
size 12{ { {3} over {8} } div { {9} over {"16"} } cdot { {6} over {5} } } {}
4
5
size 12{ { {4} over {5} } } {}
3
16
⋅
9
8
⋅
6
5
size 12{ { {3} over {"16"} } cdot { {9} over {8} } cdot { {6} over {5} } } {}
4
15
÷
2
25
⋅
9
10
size 12{ { {4} over {"15"} } div { {2} over {"25"} } cdot { {9} over {"10"} } } {}
21
30
⋅
1
1
4
÷
9
10
size 12{ { {"21"} over {"30"} } cdot 1 { {1} over {4} } div { {9} over {"10"} } } {}
8
1
3
⋅
36
75
÷
4
size 12{8 { {1} over {3} } cdot { {"36"} over {"75"} } div 4} {}
Exercises for review
(
[link] ) What is the value of 5 in the number 504,216?
(
[link] ) Find the product of 2,010 and 160.
(
[link] ) Use the numbers 8 and 5 to illustrate the commutative property of multiplication.
(
[link] ) Find the least common multiple of 6, 16, and 72.
(
[link] ) Find
8
9
size 12{ { {8} over {9} } } {} of
6
3
4
size 12{6 { {3} over {4} } } {} .