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When working with signals many times it is helpful to break up a signal into smaller, more manageable parts. Hopefully bynow you have been exposed to the concept of eigenvectors and there use in decomposing a signal into one of its possible basis.By doing this we are able to simplify our calculations of signals and systems through eigenfunctions of LTI systems .
Now we would like to look at an alternative way to represent signals, through the use of orthonormal basis . We can think of orthonormal basis as a set of building blockswe use to construct functions. We will build up the signal/vector as a weighted sum of basis elements.
The complex sinusoids for all form an orthonormal basis for .
In our Fourier series equation, , the are just another representation of .
Recall our definition of a basis : A set of vectors in a vector space is a basis if
Condition 2 in the above definition says we can decompose any vector in terms of the . Condition 1 ensures that the decomposition is unique (think about this at home).
Let us look at simple example in , where we have the following vector: Standard Basis: Alternate Basis:
In general, given a basis and a vector , how do we find the and such that
Now let us address the question posed above about finding 's in general for . We start by rewriting [link] so that we can stack our 's as columns in a 2×2 matrix.
Here is a simple example, which shows a little more detail about the above equations.
To make notation simpler, we define the following two itemsfrom the above equations:
Given a standard basis, , then we have the following basis matrix:
To get the 's, we solve for the coefficient vector in [link]
Let us look at the standard basis first and try to calculate from it. Where is the identity matrix . In order to solve for let us find the inverse of first (which is obviously very trivial in this case): Therefore we get,
Let us look at a ever-so-slightly more complicated basis of Then our basis matrix and inverse basis matrix becomes: and for this example it is given that Now we solve for and we get
Now we are given the following basis matrix and : For this problem, make a sketch of the bases and then represent in terms of and .
In order to represent in terms of and we will follow the same steps we used in the above example. And now we can write in terms of and . And we can easily substitute in our known values of and to verify our results.
We can also extend all these ideas past just and look at them in and . This procedure extends naturally to higher (>2) dimensions. Given a basis for , we want to find such that
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