<< Chapter < Page Chapter >> Page >

A committee of five is chosen from a group of 20 people. What is the probability that a specified member of the group will be on the committee?

C ( 20 , 5 ) committees; C ( 19 , 4 ) have a designated member.

P = 19 ! 4 ! 15 ! 5 ! 15 ! 20 ! = 5 / 20 = 1 / 4
Got questions? Get instant answers now!

Ten employees of a company drive their cars to the city each day and park randomly in ten spots. What is the (classical) probability that on a given day Jim willbe in place three? There are n ! equally likely ways to arrange n items (order important).

10! permutations. 1 × 9 ! permutations with Jim in place 3. P = 9 ! / 10 ! = 1 / 10 .

Got questions? Get instant answers now!

An extension of the classical model involves the use of areas. A certain region L (say of land) is taken as a reference. For any subregion A , define P ( A ) = a r e a ( A ) / a r e a ( L ) . Show that P ( ) is a probability measure on the subregions of L .

Additivity follows from additivity of areas of disjoint regions.

Got questions? Get instant answers now!

John thinks the probability the Houston Texans will win next Sunday is 0.3 and the probability the Dallas Cowboys will win is 0.7 (they are not playing each other).He thinks the probability both will win is somewhere between—say, 0.5. Is that a reasonable assumption? Justify your answer.

P ( A B ) = 0 . 5 is not reasonable. It must no greater than the minimum of P ( A ) = 0 . 3 and P ( B ) = 0 . 7 .

Got questions? Get instant answers now!

Suppose P ( A ) = 0 . 5 and P ( B ) = 0 . 3 . What is the largest possible value of P ( A B ) ? Using the maximum value of P ( A B ) , determine P ( A B c ) , P ( A c B ) , P ( A c B c ) and P ( A B ) . Are these values determined uniquely?

Draw a Venn diagram, or use algebraic expressions P ( A B c ) = P ( A ) - P ( A B ) = 0 . 2

P ( A c B ) = P ( B ) - P ( A B ) = 0 P ( A c B c ) = P ( A c ) - P ( A c B ) = 0 . 5 P ( A B ) = 0 . 5
Got questions? Get instant answers now!

For each of the following probability “assignments”, fill out the table. Which assignments are not permissible? Explain why, in each case.

P ( A ) P ( B ) P ( A B ) P ( A B ) P ( A B c ) P ( A c B ) P ( A ) + P ( B )
0.3 0.7 0.4
0.2 0.1 0.4
0.3 0.7 0.2
0.3 0.5 0
0.3 0.8 0
P ( A ) P ( B ) P ( A B ) P ( A B ) P ( A B c ) P ( A c B ) P ( A ) + P ( B )
0.3 0.7 0.4 0.6 -0.1 0.3 1.0
0.2 0.1 0.4 -0.1 -0.2 -0.3 0.3
0.3 0.7 0.2 0.8 0.1 0.5 1.0
0.3 0.5 0 0.8 0.3 0.5 0.8
0.3 0.8 0 1.1 0.3 0.8 1.1

Only the third and fourth assignments are permissible.

Got questions? Get instant answers now!

The class { A , B , C } of events is a partition. Event A is twice as likely as C and event B is as likely as the combination A or C . Determine the probabilities P ( A ) , P ( B ) , P ( C ) .

P ( A ) + P ( B ) + P ( C ) = 1 , P ( A ) = 2 P ( C ) , and P ( B ) = P ( A ) + P ( C ) = 3 P ( C ) , which implies

P ( C ) = 1 / 6 , P ( A ) = 1 / 3 , and P ( B ) = 1 / 2
Got questions? Get instant answers now!

Determine the probability P ( A B C ) in terms of the probabilities of the events A , B , C and their intersections.

P ( A B C ) = P ( A B ) + P ( C ) - P ( A C B C )

= P ( A ) + P ( B ) - P ( A B ) + P ( C ) - P ( A C ) - P ( B C ) + P ( A B C )
Got questions? Get instant answers now!

If occurrence of event A implies occurrence of B , show that P ( A c B ) = P ( B ) - P ( A ) .

P ( A B ) = P ( A ) and P ( A B ) + P ( A c B ) = P ( B ) implies P ( A c B ) = P ( B ) - P ( A ) .

Got questions? Get instant answers now!

Show that P ( A B ) P ( A ) + P ( B ) - 1 .

Follows from P ( A ) + P ( B ) - P ( A B ) = P ( A B ) 1 .

Got questions? Get instant answers now!

The set combination A B = A B c A c B is known as the disjunctive union or the symetric difference of A and B . This is the event that only one of the events A or B occurs on a trial. Determine P ( A B ) in terms of P ( A ) , P ( B ) , and P ( A B ) .

A Venn diagram shows P ( A B ) = P ( A B c ) + P ( A B c ) = P ( A ) + P ( B ) - 2 P ( A B ) .

Got questions? Get instant answers now!

Use fundamental properties of probability to show

  1. P ( A B ) P ( A ) P ( A B ) P ( A ) + P ( B )
  2. P j = 1 E j P ( E i ) P j = 1 E j j = 1 P ( E j )

A B A A B implies P ( A B ) P ( A ) P ( A B ) = P ( A ) + P ( B ) - P ( A B ) P ( A ) + P ( B ) . The general case follows similarly, with the last inequality determined by subadditivity.

Got questions? Get instant answers now!

Suppose P 1 , P 2 are probability measures and c 1 , c 2 are positive numbers such that c 1 + c 2 = 1 . Show that the assignment P ( E ) = c 1 P 1 ( E ) + c 2 P 2 ( E ) to the class of events is a probability measure. Such a combination of probability measures is known as a mixture . Extend this to

P ( E ) = i = 1 n c i P i ( E ) , where the P i are probabilities measures, c i > 0 , and i = 1 n c i = 1

Clearly P ( E ) 0 . P ( Ω ) = c 1 P 1 ( Ω ) + c 2 P 2 ( Ω ) = 1 .

E = i = 1 E i implies P ( E ) = c 1 i = 1 P 1 ( E i ) + c 2 i = 1 P 2 ( E i ) = i = 1 P ( E i )

The pattern is the same for the general case, except that the sum of two terms is replaced by the sum of n terms c i P i ( E ) .

Got questions? Get instant answers now!

Suppose { A 1 , A 2 , , A n } is a partition and { c 1 , c 2 , , c n } is a class of positive constants. For each event E , let

Q ( E ) = i = 1 n c i P ( E A i ) i = 1 n c i P ( A i )

Show that Q ( ) us a probability measure.

Clearly Q ( E ) 0 and since A i Ω = A i we have Q ( Ω ) = 1 . If

E = k = 1 E k , then P ( E A i ) = k = 1 P ( E k A i ) i

Interchanging the order of summation shows that Q is countably additive.

Got questions? Get instant answers now!

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
khuthadzo hii
Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
please help me with vectors in two dimensions
Mulaudzi Reply
how to calculate normal force
Mulaudzi
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Applied probability' conversation and receive update notifications?

Ask