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Card 11 / 19:
Use the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents.
Considering each gene separately, the cross at A will produce offspring of which half are AA and half are Aa ; B will produce all Bb ; C will produce half Cc and half cc . Proportions then are (1/2) × (1) × (1/2), or 1/4 AABbCc ; continuing for the other possibilities yields 1/4 AABbcc , 1/4 AaBbCc , and 1/4 AaBbcc . The proportions therefore are 1:1:1:1.
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