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This appendix contains outline proofs and derivations for the theorems and formulas given in early part of Chapter: The Scaling Function and Scaling Coefficients, Wavelet and Wavelet Coefficients . They are not intended to be completeor formal, but they should be sufficient to understand the ideas behind why a result is true and to give some insight into its interpretation aswell as to indicate assumptions and restrictions.

Proof 1 The conditions given by [link] and [link] can be derived by integrating both sides of

φ ( x ) = n h ( n ) M φ ( M x - n )

and making the change of variables y = M x

φ ( x ) d x = n h ( n ) M φ ( M x - n ) d x

and noting the integral is independent of translation which gives

= n h ( n ) M φ ( y ) 1 M d y .

With no further requirements other than φ L 1 to allow the sum and integral interchange and φ ( x ) d x 0 , this gives [link] as

n h ( n ) = M

and for M = 2 gives [link] . Note this does not assume orthogonality nor any specific normalization of φ ( t ) and does not even assume M is an integer.

This is the most basic necessary condition for the existence of φ ( t ) and it has the fewest assumptions or restrictions.

Proof 2 The conditions in [link] and [link] are a down-sampled orthogonality of translates by M of the coefficients which results from the orthogonality of translates of the scaling function given by

φ ( x ) φ ( x - m ) d x = E δ ( m )

in [link] . The basic scaling equation [link] is substituted for both functions in [link] giving

n h ( n ) M φ ( M x - n ) k h ( k ) M φ ( M x - M m - k ) d x = E δ ( m )

which, after reordering and a change of variable y = M x , gives

n k h ( n ) h ( k ) φ ( y - n ) φ ( y - M m - k ) d y = E δ ( m ) .

Using the orthogonality in [link] gives our result

n h ( n ) h ( n - M m ) = δ ( m )

in [link] and [link] . This result requires the orthogonality condition [link] , M must be an integer, and any non-zero normalization E may be used.

Proof 3 (Corollary 2) The result that

n h ( 2 n ) = n h ( 2 n + 1 ) = 1 / 2

in [link] or, more generally

n h ( M n ) = n h ( M n + k ) = 1 / M

is obtained by breaking [link] for M = 2 into the sum of the even and odd coefficients.

n h ( n ) = k h ( 2 k ) + k h ( 2 k + 1 ) = K 0 + K 1 = 2 .

Next we use [link] and sum over n to give

n k h ( k + 2 n ) h ( k ) = 1

which we then split into even and odd sums and reorder to give:

n k h ( 2 k + 2 n ) h ( 2 k ) + k h ( 2 k + 1 + 2 n ) h ( 2 k + 1 ) = k n h ( 2 k + 2 n ) h ( 2 k ) + k n h ( 2 k + 1 + 2 n ) h ( 2 k + 1 ) = k K 0 h ( 2 k ) + k K 1 h ( 2 k + 1 ) = K 0 2 + K 1 2 = 1 .

Solving [link] and [link] simultaneously gives K 0 = K 1 = 1 / 2 and our result [link] or [link] for M = 2 .

If the same approach is taken with [link] and [link] for M = 3 , we have

n x ( n ) = n x ( 3 n ) + n x ( 3 n + 1 ) + n x ( 3 n + 2 ) = 3

which, in terms of the partial sums K i , is

n x ( n ) = K 0 + K 1 + K 2 = 3 .

Using the orthogonality condition [link] as was done in [link] and [link] gives

K 0 2 + K 1 2 + K 2 2 = 1 .

Equation [link] and [link] are simultaneously true if and only if K 0 = K 1 = K 2 = 1 / 3 . This process is valid for any integer M and any non-zero normalization.

Proof 3 If the support of φ ( x ) is [ 0 , N - 1 ] , from the basic recursion equation with support of h ( n ) assumed as [ N 1 , N 2 ] we have

φ ( x ) = n = N 1 N 2 h ( n ) 2 φ ( 2 x - n )

where the support of the right hand side of [link] is [ N 1 / 2 , ( N - 1 + N 2 ) / 2 ) . Since the support of both sides of [link] must be the same, the limits on the sum, or, the limits on the indices of the non zero h ( n ) are such that N 1 = 0 and N 2 = N , therefore, the support of h ( n ) is [ 0 , N - 1 ] .

Proof 4 First define the autocorrelation function

a ( t ) = φ ( x ) φ ( x - t ) d x

and the power spectrum

A ( ω ) = a ( t ) e - j ω t d t = φ ( x ) φ ( x - t ) d x e - j ω t d t

which after changing variables, y = x - t , and reordering operations gives

Questions & Answers

what does the ideal gas law states
Joy Reply
Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
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what is the change in momentum of a body?
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what is a capacitor?
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Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
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please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
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A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
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50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
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field is a region of space under the influence of some physical properties
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Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
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Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
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Source:  OpenStax, Intermodular linking test collection. OpenStax CNX. Sep 09, 2015 Download for free at http://legacy.cnx.org/content/col11841/1.4
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