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I can actually write down what that is because XI is Gaussian with parameter mu and variance lambda lambda transpose times psi, so you can actually write this down as one over two pi to the N over two determined of – and then times E to the minus one half X of – so that’s my formula for the density of a Gaussian that has mean mu and covariance lambda lambda transpose plus psi. So this is my likelihood of the parameters given a training set. And one thing you could do is actually take this likelihood and try to maximize it in terms of the parameters, try to find the [inaudible] the parameters. But if you do that you find that – if you sort of try – take [inaudible]to get the law of likelihood, take derivatives, set derivatives equal to zero, you find that you’ll be unable to solve for the maximum of this analytically. You won’t be able to solve this [inaudible] likelihood estimation problem.

If you take the derivative of this with respect to the parameters, set the derivatives equal to zero and try to solve for the value of the parameters lambda, mu, and psi [inaudible] so you won’t be able to do that [inaudible]. So what we’ll use instead to estimate the parameters in a factor analysis model will be the EM algorithm.

Student: Why is the law of likelihood P of X and not P of X [inaudible] X and Z or something?

Instructor (Andrew Ng) :Oh, right. So the question is why is the likelihood P of X and not P of X given Z or P of X and Z. The answer is let’s see – we’re in the – so by analogy to the mixture of Gaussian distributions models, we’re given a training set that just comprises a set of unlabeled training examples that – for convenience for whatever reason, it’s easier for me to write down a model that defines the joint distribution on P of X comma Z.

But what I would like to do is really maximize – as a function of my parameters – I’m using theta as a shorthand to denote all the parameters of the model – I want to maximize the probability of the data I actually observe. And this would be actually [inaudible] theta [inaudible]from I equals one to M, and this is really integrating out Z.

So I only ever get to observe the Xs and the Zs are latent random variables or hidden random variables. And so what I’d like to do is do this maximization in which I’ve implicitly integrated out Z. Does that make sense? Actually, are there other questions about the factor analysis models? Okay. So here’s the EM algorithm. In the E step, we compute the conditional distribution of ZI given XI in our current setting of the parameters. And in the M step, we perform this maximization. And if this looks a little bit different from the previous versions of EM that you’ve seen, the only difference is that now I’m integrating over ZI because ZI is now a Gaussian random variable, is now this continuous value thing, so rather than summing over ZI, I now integrate over ZI. And if you replace [inaudible] of a sum, you [inaudible]ZI then this is exactly the M step you saw when we worked it out from the mixture of Gaussian [inaudible].

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
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Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
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Source:  OpenStax, Machine learning. OpenStax CNX. Oct 14, 2013 Download for free at http://cnx.org/content/col11500/1.4
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