1.1 X and y-intercepts

x-intercept: None since $1\neq 0$

y-intercept: (0, $\frac{1}{2}$ ) since $\frac{1}{0+2}=\frac{1}{2}$

x-intercept: ( $\frac{1}{3}$ ,0) since $1-3x=0$ , $-3x=-1$ , $x=\frac{1}{3}$

y-intercept: (0,1) since $\frac{1-3\times 0}{1-0}=1$

x-intercept: (0,0) since $x^2=0$ , $x=0$

y-intercept: (0,0) since $\frac{0^2}{0^2+9}=\frac{0}{9}=0$ or because the x-intercept is (0,0)

x-intercept: (-1,0) since $\sqrt{x+1}=0$ , $x+1=0$ , $x=-1$

y-intercept: (0, $\frac{1}{4}$ ) since $\frac{\sqrt{0+1}}{(0-2)^2}=\frac{\sqrt{1}}{-2^2}=\frac{1}{4}$

x-intercept: (0,0) since $3x=0$ , $x=0$

y-intercept: (0,0) since the x-intercept is (0,0)

x-intercept: (2,0) since $\frac{1}{x-3}+1=0$ , $\frac{1}{x-3}=-1$ , $-x+3=1$ , $-x=-2$ , $x=2$

y-intercept: (0, $\frac{2}{3}$ ) since $\frac{1}{0-3}+1=\frac{-1}{3}+1=\frac{2}{3}$

x-intercepts: (-2,0), (2,0) since $x^2-4=0$ , $x^2=4$ , $x=-2$ , $x=2$

y-intercept: (0, -4) since $\frac{0^2-4}{\sqrt{0+1}}=\frac{-4}{\sqrt{1}}=-4$

x-intercept: None since $4+\frac{5}{x^2+2}=0$ , $\frac{5}{x^2+2}=-4$ , $-4x^2-8=5$ , $-4x^2=13$ , $x^2=\frac{13}{4}$ , a number squared will never be a negative number, so there is no x-intercept

y-intercept: (0, $\frac{13}{2}$ ) since $4+\frac{5}{0^2+2}=4+\frac{5}{2}=\frac{13}{2}$

x-intercept: ( $\frac{2}{5}$ , 0) since $\sqrt{5x-2}=0$ , $5x-2=0$ , $5x=2$ , $x=\frac{2}{5}$

y-intercept: None since $y=\frac{\sqrt{5\times 0-2}}{0-3}$ takes the square root of a negative number.

x-intercept: (2,0) since $x^3-8=0$ , $(x-2)(x^2+2x+4)=0$ , $x=2$

y-intercept: (0,-8) since $\frac{0^3-8}{0^2+1}=\frac{-8}{1}=-8$