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The prime factor algorithm (PFA) and the Winograd Fourier transform algorithm (WFTA) are methods for efficiently calculatingthe DFT which use, and in fact, depend on the Type-1 index map from Multidimensional Index Mapping: Equation 10 and Multidimensional Index Mapping: Equation 6 . The use of this index map preceded Cooley and Tukey's paper [link] , [link] but its full potential was not realized until it was combined with Winograd's short DFT algorithms.The modern PFA was first presented in [link] and a program given in [link] . The WFTA was first presented in [link] and programs given in [link] , [link] .

The number theoretic basis for the indexing in these algorithms may, at first, seem more complicated than in theCooley-Tukey FFT; however, if approached from the general index mapping point of view of Multidimensional Index Mapping , it is straightforward, and part of a common approach to breaking large problems intosmaller ones. The development in this section will parallel that in The Cooley-Tukey Fast Fourier Transform Algorithm .

The general index maps of Multidimensional Index Mapping: Equation 6 and Multidimensional Index Mapping: Equation 12 must satisfy the Type-1 conditions of Multidimensional Index Mapping: Equation 7 and Multidimensional Index Mapping: Equation 10 which are

K 1 = a N 2 and K 2 = b N 1 with ( K 1 , N 1 ) = ( K 2 , N 2 ) = 1
K 3 = c N 2 and K 4 = d N 1 with ( K 3 , N 1 ) = ( K 4 , N 2 ) = 1

The row and column calculations in Multidimensional Index Mapping: Equation 15 are uncoupled by Multidimensional Index Mapping: Equation 16 which for this case are

( ( K 1 K 4 ) ) N = ( ( K 2 K 3 ) ) N = 0

In addition, to make each short sum a DFT, the K i must also satisfy

( ( K 1 K 3 ) ) N = N 2 a n d ( ( K 2 K 4 ) ) N = N 1

In order to have the smallest values for K i , the constants in [link] are chosen to be

a = b = 1 , c = ( ( N 2 - 1 ) ) N , d = ( ( N 1 - 1 ) ) N

which gives for the index maps in [link]

n = ( ( N 2 n 1 + N 1 n 2 ) ) N
k = ( ( K 3 k 1 + K 4 k 2 ) ) N

The frequency index map is a form of the Chinese remainder theorem. Using these index maps, the DFT in Multidimensional Index Mapping: Equation 15 becomes

X = n 2 = 0 N 2 - 1 n 1 = 0 N 1 - 1 x W N 1 n 1 k 1 W N 2 n 2 k 2

which is a pure two-dimensional DFT with no twiddle factors and the summations can be done in either order. Choices other than [link] could be used. For example, a = b = c = d = 1 will cause the input and output index map to be the same and, therefore,there will be no scrambling of the output order. The short summations in (96), however, will no longer be short DFT's [link] .

An important feature of the short Winograd DFT's described in Winograd’s Short DFT Algorithms that is useful for both the PFA and WFTA is the fact that the multiplier constants in Winograd’s Short DFT Algorithms: Equation 6 or Winograd’s Short DFT Algorithms: Equation 8 are either real or imaginary, never a general complex number. For thatreason, multiplication by complex data requires only two real multiplications, not four. That is a very significant feature. It isalso true that the j multiplier can be commuted from the D operator to the last part of the A T operator. This means the D operator has only real multipliers and the calculations on real data remains real until the last stage. This can be seen by examining theshort DFT modules in [link] , [link] and in the appendices.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Fast fourier transforms. OpenStax CNX. Nov 18, 2012 Download for free at http://cnx.org/content/col10550/1.22
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