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Remember that if you put a number in front of a molecule, that number applies to the whole molecule. For example, if you write , this means that there are 2 molecules of water. In other words, there are 4 hydrogen atoms and 2 oxygen atoms. If we write , this means that there are 3 molecules of . In other words there are 3 hydrogen atoms and 3 chlorine atoms in total. In the first example, 2 is the coefficient and in the second example, 3 is the coefficient.
You will need: coloured balls (or marbles), prestik, a sheet of paper and coloured pens.
We will try to balance the following equation:
Count the number of balls on the left and the number on the right. Do you have the same number of each colour on both sides? If not the equation is not balanced. How many balls will you have to add to each side to make the number of balls the same? How would you add these balls?
You should find that you need 4 balls of one colour for and 3 pairs of balls of another colour (i.e. 6 balls in total) for on the left side. On the right side you should find that you need 2 clusters of balls for . We say that the balanced equation is:
Repeat this process for the following reactions:
When balancing a chemical equation, there are a number of steps that need to be followed.
Balance the following equation:
Reactants: ; and
Products: ; and
The equation is not balanced since there are 2 chlorine atoms in the product and only 1 in the reactants. If we add a coefficient of 2 to the to increase the number of and atoms in the reactants, the equation will look like this:
If we count the atoms on each side of the equation, we find the following:
Reactants: ; and
Products: ; and
The equation is balanced. The final equation is:
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