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The rule for angular acceleration
If the magnitude of the angular velocity increases in time, then the angular accelerationvector has the same direction as that of the angular velocity. If the magnitude of the angular velocitydecreases in time, then the angular acceleration vector has the opposite direction as that of theangular velocity.
Defining torque as a vector quantity
The magnitude of a torque is the product of two terms:
Define theta as the angle between the line and the force vector F (not the tangential component of the force vector but the force vector itself). Then themagnitude of the tangential force vector is given by
Ft = Fmag*sin(theta)
where
Define a vector R
Let R represent a vector that lies along the line from the axis of rotation to the point where the force acts with its tail at the axis of rotation. I will refer tothe magnitude of this vector as Rmag
Doing a little algebra, we can write
T = r*Ft, or
Tvec = Rmag*Fmag*sin(theta)
where
The cross product
Why do I refer to Tvec as a vector in the above equation?
You learned in an earlier module that the cross product of two vectors A and B is given by
AxB = Amag*Bmag*sin(angle between A and B)
where
The torque vector
Comparing the torque vector with the cross product , we determine that
Tvec = RxF
Figure 4 . The torque vector . |
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Tvec = RxF where
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The direction of the torque vector
Recall from the earlier module that the direction of Tvec is perpendicular to both R and F and obeys the right-hand rule in terms of its absolute direction.
The relationship of torque and rotational inertia
Combining this with what we learned earlier about the relationship among torque, rotational inertia, and rotational acceleration, we can write
Tvec = I*A
Figure 5 . A general equation for net torque. |
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Tvec = I*A where
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A general equation for net torque
The equation shown in Figure 5 is a general equation for net torque. The net torque about an axis of rotation is equal to the product of the rotational inertia about that axis and the angular acceleration.
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