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This module is part of a collection of modules that present topics covered in a PreCalculus (MATH 1508) class at the University of Texas at El Paso.

Exponents

Introduction

Exponentiation is a mathematical operation that is employed extensively in applications in fields that range from science and engineering to finance and economics. This module will begin with a brief discussion of the terminology and the mathematics involved with exponentiation. This will be followed with some applications of exponentiation in science and engineering.

Scientific notation and engineering notation are introduced in this module as two common means for expressing physical quantities. Each of these representational schemes involve the use of exponents. Applications are presented on topics including electrical power, gravitatitational force and electrostatic force are presented as a means for illustrating how exponentiation can be useful in problem solving.

Definition and terminology

Exponentiation is an operation in mathematics that makes use of two numbers known as the base ( x ) and the exponent ( n ) and is expressed as

x n size 12{x rSup { size 8{n} } } {}

In this module, we will restrict our discussion to situations where the exponent ( n ) is an integer. Being an integer, the exponent may be positive, negative or equal to 0. We will consider each case below.

If the exponent n is a positive integer, then the operation of exponentiation is equivalent to the multiplication of the base x with itself a total of n times.

In the situation where the base ( x ) is 5 and the exponent ( n ) is 3, we obtain the result

5 3 = 5 5 5 = 125 size 12{5 rSup { size 8{3} } =5 cdot 5 cdot 5="125"} {}

Now, let us the case where the exponent is a negative integer. In this case, the process of exponentiation is equivalent to dividing one by the base x by n times.

Let us consider an example where the base ( x ) is 5, but now the exponent ( n ) is -3. In this example, we obtain the result

5 3 = 1 5 5 5 = 1 125 = 0 . 008 size 12{5 rSup { size 8{ - 3} } = { {1} over {5 cdot 5 cdot 5} } = { {1} over {"125"} } =0 "." "008"} {}

Suppose that we form the product of 5 3 size 12{5 rSup { size 8{3} } } {} with 5 3 size 12{5 rSup { size 8{ - 3} } } {} .

5 3 × 5 3 = 125 × 0 . 008 size 12{5 rSup { size 8{3} } times 5 rSup { size 8{ - 3} } ="125" times 0 "." "008"} {}
5 3 3 = 1 size 12{5 rSup { size 8{3 - 3} } =1} {}
5 0 = 1 size 12{5 rSup { size 8{0} } =1} {}

The result of the multiplication reminds us of the property of exponents that states whenever a base ( x ) is raised to an exponent ( n ) that is zero, the result is 1.

Scientific and engineering notation

One of the most important uses of exponents in the fields of science and engineering is that of scientific notation. As is often the case, in the fields of science and engineering one often deals with numbers that are extremely large or extremely small. Scientific notation is an effective means for writing such number that makes use of exponents. In many cases, scientific notation enables one to write very large or very small numbers in a manner that is more convenient, insightful and compact that writing numbers using decimal notation.

Numbers can be written in scientific notation in the following form

a × 10 b size 12{a` times `"10" rSup { size 8{b} } } {}

where a is the coefficient which can be any real number in the range 1<|a|<10 and b is an integer that represents the exponent.

Example (Avogadro’s Number)

In chemistry, the quantity of an element having a weight in grams numerically equal to that element’s atomic weight is the gram atomic weight of that element. This quantity is often refererred to as a gram atom . A gram atom of any element contains the same number of atoms as the gram atom of any other element. The number of atoms in any gram atom is called Avogadro’s number (N). Through meticulous experimental study, the value of Avogadro’s number has been determined as

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Math 1508 (laboratory) engineering applications of precalculus. OpenStax CNX. Aug 24, 2011 Download for free at http://cnx.org/content/col11337/1.3
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