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In [link] above, how much should each person get for his efforts?

We choose the following variables.

x = Farmer's pay size 12{x="Farmer's pay"} {}
y = Carpenter's pay size 12{y=" Carpenter's pay"} {}
z = Tailor's pay size 12{z=" Tailor's pay"} {}

As we said earlier, in this model input must equal output. That is, the amount paid by each equals the amount received by each.

Let us say the farmer gets paid x size 12{x} {} dollars. Let us now look at the farmer's expenses. The farmer uses up 40% of his own production, that is, of the x size 12{x} {} dollars he gets paid, he pays himself . 40 x size 12{ "." "40"x} {} dollars, he pays . 40 y size 12{ "." "40"y} {} dollars to the carpenter, and . 30 z size 12{ "." "30"z} {} to the tailor. Since the expenses equal the wages, we get the following equation.

x = . 40 x + . 40 y + . 30 z size 12{x= "." "40"x+ "." "40"y+ "." "30"z} {}

In the same manner, we get

y = . 40 x + . 30 y + . 20 z size 12{y= "." "40"x+ "." "30"y+ "." "20"z} {}
z = . 20 x + . 30 y + . 50 z size 12{z= "." "20"x+ "." "30"y+ "." "50"z} {}

The above system can be written as

x y z = . 40 . 40 . 30 . 40 . 30 . 20 . 20 . 30 . 50 x y z size 12{ left [ matrix { x {} ##y {} ## z} right ]= left [ matrix {"." "40" {} # "." "40" {} # "." "30" {} ## "." "40" {} # "." "30" {} # "." "20" {} ##"." "20" {} # "." "30" {} # "." "50"{} } right ]left [ matrix { x {} ##y {} ## z} right ]} {}

This system is often referred to as

X = AX size 12{X= ital "AX"} {}

Simplification results in

. 60 x . 40 y . 30 z = 0 size 12{ "." "60"x - "." "40"y - "." "30"z=0} {}
. 40 x + . 70 y . 20 z = 0 size 12{ - "." "40"x+ "." "70"y - "." "20"z=0} {}
. 20 x . 30 y + . 50 z = 0 size 12{ - "." "20"x - "." "30"y+ "." "50"z=0} {}

Solving for x size 12{x} {} , y size 12{y} {} , and z size 12{z} {} using the Gauss-Jordan method, we get

x = 29 26 t size 12{x= { {"29"} over {"26"} } t} {}       y = 12 13 t size 12{y= { {"12"} over {"13"} } t} {}       and       z = t size 12{z=t} {}

Since we are only trying to determine the proportions of the pay, we can choose t to be any value. Suppose we let t = $ 2600 size 12{t=$"2600"} {} , then we get

x = $ 2900 size 12{x=$"2900"} {}       y = $ 2400 size 12{y=$"2400"} {}       and       z = $ 2600 size 12{z=$"2600"} {}
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The use of a calculator in solving these problems is strongly recommended. Although we at De Anza College use TI-85 calculators, any calculator that handles matrices will do.

The Open Model

The open model is more realistic, as it deals with the economy where sectors of the economy not only satisfy each others needs, but they also satisfy some outside demands. In this case, the outside demands are put on by the consumer. But the basic assumption is still the same; that is, whatever is produced is consumed.

Let us again look at a very simple scenario. Suppose the economy consists of three people, the farmer F size 12{F} {} , the carpenter C size 12{C} {} , and the tailor T size 12{T} {} . A part of the farmer's production is used by all three, and the rest is used by the consumer. In the same manner, a part of the carpenter's and the tailor's production is used by all three, and rest is used by the consumer.

Let us assume that whatever the farmer produces, 20% is used by him, 15% by the carpenter, 10% by the tailor, and the consumer uses the other 40 billion dollars worth of the food. Ten percent of the carpenter's production is used by him, 25% by the farmer, 5% by the tailor, and 50 billion dollars worth by the consumer. Fifteen percent of the clothing is used by the tailor, 10% by the farmer, 5% by the carpenter, and the remaining 60 billion dollars worth by the consumer. We write the internal consumption in the following table, and express the demand as the matrix D.

F size 12{F} {} produces C size 12{C} {} produces T size 12{T} {} produces
F size 12{F} {} uses .20 .25 .10
C size 12{C} {} uses .15 .10 .05
T size 12{T} {} uses .10 .05 .15

The consumer demand for each industry in billions of dollars is given below.

D = 40 50 60 size 12{D= left [ matrix { "40" {} ##"50" {} ## "60"} right ]} {}

In [link] , what should be, in billions of dollars, the required output by each industry to meet the demand given by the matrix D?

We choose the following variables.

x = Farmer's output size 12{x="Farmer's output"} {}
y = Carpenter's output size 12{y=" Carpenter's output"} {}
z = Tailor's output size 12{z=" Tailor's output"} {}

In the closed model, our equation was X = AX size 12{X = ital "AX"} {} , that is, the total input equals the total output. This time our equation is similar with the exception of the demand by the consumer.

So our equation for the open model should be X = AX + D size 12{X= ital "AX"+D} {} , where D size 12{D} {} represents the demand matrix. We express it as follows:

X = AX + D size 12{X= ital "AX"+D} {}
x y z = . 20 . 25 . 10 . 15 . 10 . 05 . 10 . 05 . 15 x y z + 40 50 60 size 12{ left [ matrix { x {} ##y {} ## z} right ]= left [ matrix {"." "20" {} # "." "25" {} # "." "10" {} ## "." "15" {} # "." "10" {} # "." "05" {} ##"." "10" {} # "." "05" {} # "." "15"{} } right ]left [ matrix { x {} ##y {} ## z} right ]+ left [ matrix {"40" {} ## "50" {} ##"60" } right ]} {}

To solve this system, we write it as

X = AX + D size 12{X= ital "AX"+D} {}
I A X = D size 12{ left (I - A right )X=D} {}

where I is a 3 by 3 identity matrix

X = I A 1 D size 12{X= left (I - A right ) rSup { size 8{ - 1} } D} {}
I A = . 80 . 25 . 10 . 15 . 90 . 05 . 10 . 05 . 85 size 12{I - A= left [ matrix { "." "80" {} # - "." "25" {} # - "." "10" {} ##- "." "15" {} # "." "90" {} # - "." "05" {} ## - "." "10" {} # - "." "05" {} # "." "85"{}} right ]} {}
I A 1 = 1 . 3445 . 3835 . 1807 . 2336 1 . 1814 . 097 . 1719 . 1146 1 . 2034 size 12{ left (I - A right ) rSup { size 8{ - 1} } = left [ matrix { 1 "." "3445" {} # "." "3835" {} # "." "1807" {} ##"." "2336" {} # 1 "." "1814" {} # "." "097" {} ## "." "1719" {} # "." "1146" {} # 1 "." "2034"{}} right ]} {}
X = 1 . 3445 . 3835 . 1807 . 2336 1 . 1814 . 097 . 1719 . 1146 1 . 2034 40 50 60 size 12{X= left [ matrix { 1 "." "3445" {} # "." "3835" {} # "." "1807" {} ##"." "2336" {} # 1 "." "1814" {} # "." "097" {} ## "." "1719" {} # "." "1146" {} # 1 "." "2034"{}} right ] left [ matrix {"40" {} ## "50" {} ##"60" } right ]} {}
X = 83 . 7999 74 . 2341 84 . 8138 size 12{X= left [ matrix { "83" "." "7999" {} ##"74" "." "2341" {} ## "84" "." "8138"} right ]} {}

Therefore, the three industries must produce the following amount of goods in billions of dollars.

Farmer = $ 83 . 7999 size 12{"Farmer"=$"83" "." "7999"} {}       Carpenter = $ 74 . 2341 size 12{"Carpenter"=$"74" "." "2341"} {}      Tailor = $ 84 . 813 size 12{"Tailor"=$"84" "." "813"} {}

We will do one more problem like the one above, except this time we give the amount of internal and external consumption in dollars and ask for the proportion of the amounts consumed by each of the industries. In other words, we ask for the matrix A.

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Suppose an economy consists of three industries F size 12{F} {} , C size 12{C} {} , and T size 12{T} {} . Again, each of the industries produces for internal consumption among themselves, as well as, the external demand by the consumer. The following table gives information about the use of each industry's production in dollars.

F size 12{F} {} C size 12{C} {} T size 12{T} {} Demand Total
F size 12{F} {} 40 50 60 100 250
C size 12{C} {} 30 40 40 110 220
T size 12{T} {} 20 30 30 120 200

The first row says that of the $250 dollars worth of production by the industry F size 12{F} {} , $40 is used by F size 12{F} {} , $50 is used by C size 12{C} {} , $60 is used by T size 12{T} {} , and the remainder of $100 is used by the consumer. The other rows are described in a similar manner.

Find the proportion of the amounts consumed by each of the industries. In other words, find the matrix A.

Once again, the total input equals the total output.

We are being asked to determine the following:

How much of the production of each of the three industries, F size 12{F} {} , C size 12{C} {} , and T size 12{T} {} is required to produce one unit of F size 12{F} {} ? In the same way, how much of the production of each of the three industries, F size 12{F} {} , C size 12{C} {} , and T size 12{T} {} is required to produce one unit of C size 12{C} {} ? And finally, how much of the production of each of the three industries, F size 12{F} {} , C size 12{C} {} , and T size 12{T} {} is required to produce one unit of T size 12{T} {} ?

Since we are looking for proportions, we need to divide the production of each industry by the total production for each industry.

We analyze as follows:

To produce 250 units of F size 12{F} {} , we need to use 40 units of F size 12{F} {} , 30 units of C size 12{C} {} , and 20 units of T size 12{T} {} .

Therefore, to produce 1 unit of F size 12{F} {} , we need to use 40/250 units of F size 12{F} {} , 30/250 units of C size 12{C} {} , and 20/250 units of T size 12{T} {} .

To produce 220 units of C size 12{C} {} , we need to use 50 units of F size 12{F} {} , 40 units of C size 12{C} {} , and 30 units of T size 12{T} {} .

Therefore, to produce 1 unit of C size 12{C} {} , we need to use 50/220 units of F size 12{F} {} , 40/220 units of C size 12{C} {} , and 30/220 units of T size 12{T} {} .

To produce 200 units of T size 12{T} {} , we need to use 60 units of F size 12{F} {} , 40 units of C size 12{C} {} , and 30 units of T size 12{T} {} .

Therefore, to produce 1 unit of T size 12{T} {} , we need to use 60/200 units of F size 12{F} {} , 40/200 units of C size 12{C} {} , and 30/200 units of T size 12{T} {} .

We obtain the following matrix.

A = 40 / 250 50 / 220 60 / 200 30 / 250 40 / 220 40 / 220 20 / 250 30 / 220 30 / 220 size 12{A= left [ matrix { "40"/"250" {} # "50"/"220" {} # "60"/"200" {} ##"30"/"250" {} # "40"/"220" {} # "40"/"220" {} ## "20"/"250" {} # "30"/"220" {} # "30"/"220"{}} right ]} {}

or

A = . 1600 . 2273 . 3000 . 1200 . 1818 . 2000 . 0800 . 1364 . 1500 size 12{A= left [ matrix { "." "1600" {} # "." "2273" {} # "." "3000" {} ##"." "1200" {} # "." "1818" {} # "." "2000" {} ## "." "0800" {} # "." "1364" {} # "." "1500"{}} right ]} {}

Clearly

AX + D = X size 12{ ital "AX"+D=X} {}
40 / 250 50 / 220 60 / 200 30 / 250 40 / 220 40 / 200 20 / 250 30 / 220 30 / 200 250 220 200 + 100 110 120 = 250 220 200 size 12{ left [ matrix { "40"/"250" {} # "50"/"220" {} # "60"/"200" {} ##"30"/"250" {} # "40"/"220" {} # "40"/"200" {} ## "20"/"250" {} # "30"/"220" {} # "30"/"200"{}} right ] left [ matrix {"250" {} ## "220" {} ##"200" } right ]+ left [ matrix { "100" {} ##"110" {} ## "120"} right ]= left [ matrix {"250" {} ## "220" {} ##"200" } right ]} {}
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We summarize as follows:

Leontief's models

    The closed model

  1. All consumption is within the industries. There is no external demand.
  2. Input = Output size 12{"Input"=" Output"} {}
  3. X = AX size 12{X= ital "AX"} {} or I A X = 0 size 12{ left (I - A right )X=0} {}

    The open model

  1. In addition to internal consumption, there is an outside demand by the consumer.
  2. Input = Output size 12{"Input "=" Output"} {}
  3. X = AX + D size 12{X= ital "AX"+D} {} or X = I A 1 D size 12{X= left (I - A right ) rSup { size 8{ - 1} } D} {}
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Source:  OpenStax, Applied finite mathematics. OpenStax CNX. Jul 16, 2011 Download for free at http://cnx.org/content/col10613/1.5
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