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Let U = red, orange, yellow, green, blue, indigo, violet size 12{U= left lbrace "red, orange, yellow, green, blue, indigo, violet" right rbrace } {} , P = red, yellow, blue size 12{P= left lbrace "red, yellow, blue" right rbrace } {} , Q = red, green size 12{Q= left lbrace "red, green" right rbrace } {} , and R = orange, green, indigo size 12{R= left lbrace "orange, green, indigo" right rbrace } {} . Find P Q ¯ R ˉ size 12{ {overline {P union Q}} intersection { bar {R}}} {} .

We do the problems in steps.

P Q = red, yellow, blue, green P Q ¯ = orange, indigo, violet R ˉ = red, yellow, blue, violet P Q ¯ R ˉ = violet size 12{ matrix { P union Q= left lbrace "red, yellow, blue, green" right rbrace {} ##{overline {P union Q}} = left lbrace "orange, indigo, violet" right rbrace {} ## { bar {R}}= left lbrace "red, yellow, blue, violet" right rbrace {} ##{overline {P union Q}} intersection { bar {R}}= left lbrace "violet" right rbrace } } {}
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We now use Venn diagrams to illustrate the relations between sets. In the late 1800s, an English logician named John Venn developed a method to represent relationship between sets. He represented these relationships using diagrams, which are now known as Venn diagrams. A Venn diagram represents a set as the interior of a circle. Often two or more circles are enclosed in a rectangle where the rectangle represents the universal set. To visualize an intersection or union of a set is easy. In this section, we will mainly use Venn diagrams to sort various populations and count objects.

Suppose a survey of car enthusiasts showed that over a certain time period, 30 drove cars with automatic transmissions, 20 drove cars with standard transmissions, and 12 drove cars of both types. If every one in the survey drove cars with one of these transmissions, how many people participated in the survey?

We will use Venn diagrams to solve this problem.

Let the set A size 12{A} {} represent those car enthusiasts who drove cars with automatic transmissions, and set S size 12{S} {} represent the car enthusiasts who drove the cars with standard transmissions. Now we use Venn diagrams to sort out the information given in this problem.

Since 12 people drove both cars, we place the number 12 in the region common to both sets.

The Venn diagrams show that 12 people drove both automatic and standard transmission. While only 18 drove automatic and 8 drove standard. The Venn diagrams show that 12 people drove both automatic and standard transmission. While only 18 drove automatic and 8 drove standard. The Venn diagrams show that 12 people drove both automatic and standard transmission. While only 18 drove automatic and 8 drove standard.

Because 30 people drove cars with automatic transmissions, the circle A must contain 30 elements. This means x + 12 = 30 , or x = 18 . Similarly, since 20 people drove cars with standard transmissions, the circle B must contain 20 elements, or y + 12 = 20 which in turn makes y = 8 .

Now that all the information is sorted out, it is easy to read from the diagram that 18 people drove cars with automatic transmissions only, 12 people drove both types of cars, and 8 drove cars with standard transmissions only. Therefore, 18 + 12 + 8 = 38 people took part in the survey.

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A survey of 100 people in California indicates that 60 people have visited Disneyland, 15 have visited Knott's Berry Farm, and 6 have visited both. How many people have visited neither place?

The problem is similar to the one in [link] .

Let the set D size 12{D} {} represent the people who have visited Disneyland, and K size 12{K} {} the set of people who have visited Knott's Berry Farm.

The figure shows that everything in the box is equals U. The Venn diagram shows that D has 54 and that K has 9, while D and K have 6. While x is equal to 31 and is not included in D or K. The figure shows that everything in the box is equals U. The Venn diagram shows that D has 54 and that K has 9, while D and K have 6. While x is equal to 31 and is not included in D or K.

We fill the three regions associated with the sets D and K in the same manner as before. Since 100 people participated in the survey, the rectangle representing the universal set U must contain 100 objects. Let x represent those people in the universal set that are neither in the set D nor in K. This means 54 + 6 + 9 + x = 100 , or x = 31 .

Therefore, there are 31 people in the survey who have visited neither place.

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A survey of 100 exercise conscious people resulted in the following information:

  • 50 jog, 30 swim, and 35 cycle
  • 14 jog and swim
  • 7 swim and cycle
  • 9 jog and cycle
  • 3 people take part in all three activities
  1. How many jog but do not swim or cycle?
  2. How many take part in only one of the activities?
  3. How many do not take part in any of these activities?

Let J size 12{J} {} represent the set of people who jog, S size 12{S} {} the set of people who swim, and C size 12{C} {} who cycle.

In using Venn diagrams, our ultimate aim is to assign a number to each region. We always begin by first assigning the number to the innermost region and then working our way out.

The figure shows that everything in the square is equal to U. The Venn diagram shows that S,J and C have three in common, and J and C have 6 in common. While S and J have 11 in common and S and C have 4. Where S only has 12, C only has 22, and J only has 30. The remaining 12 have no relation to S, J, or C. The figure shows that everything in the square is equal to U. The Venn diagram shows that S,J and C have three in common, and J and C have 6 in common. While S and J have 11 in common and S and C have 4. Where S only has 12, C only has 22, and J only has 30. The remaining 12 have no relation to S, J, or C. The figure shows that everything in the square is equal to U. The Venn diagram shows that S,J and C have three in common, and J and C have 6 in common. While S and J have 11 in common and S and C have 4. Where S only has 12, C only has 22, and J only has 30. The remaining 12 have no relation to S, J, or C.

We place a 3 in the innermost region of [link] because it represents the number of people who participate in all three activities. Next we compute x, y and z.

Since 14 people jog and swim, x + 3 = 14 , or x = 11 .

The fact that 9 people jog and cycle results in y + 3 = 9 , or y = 6 .

Since 7 people swim and cycle, z + 3 = 7 , or z = 4 .

This information is depicted in [link] .

Now we proceed to find the unknowns m, n and p.

Since 50 people jog, m + 11 + 6 + 3 = 50 , or m = 30 .

Thirty people swim, therefore, n + 11 + 4 + 3 = 30 , or n = 12 .

Thirty five people cycle, therefore, p + 6 + 4 + 3 = 35 , or p = 22 .

By adding all the entries in all three sets, we get a sum of 88. Since 100 people were surveyed, the number inside the universal set but outside of all three sets is 100 – 88, or 12.

In [link] , the information is sorted out, and the questions can readily be answered.

  1. The number of people who jog but do not swim or cycle is 30.
  2. The number who take part in only one of these activities is 30 + 12 + 22 = 64 .
  3. The number of people who do not take part in any of these activities is 12.
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Source:  OpenStax, Applied finite mathematics. OpenStax CNX. Jul 16, 2011 Download for free at http://cnx.org/content/col10613/1.5
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