This module covers some properties of radicals.
What is
? Many students will answer quickly that the answer is
and have a very difficult time believing this answer is wrong. But it is wrong.
is
I’m fudging a bit here:
is
only if you ignore negative numbers. For instance, if
, then
, and
is 3; so in that case,
is not
. In general,
. However, this subtlety is not relevant to the overall point, which is that you cannot break up two terms that are added under a radical.
and
is 3, but
is not
.
Why not? Remember that
is asking a question: “what
squared gives the answer
?” So
is not an answer, because
,
not
.
As an example, suppose
. So
. But
.
If two numbers are
added or
subtracted under a square root, you cannot split them up. In symbols:
or, to put it another way,
cannot, in fact, be simplified at all. It is a perfectly valid function, but cannot be rewritten in a simpler form.
How about
? By analogy to the previous discussion, you might expect that this cannot be simplified either. But in fact, it can be simplified:
Why? Again,
is asking “what
squared gives the answer
?” The answer is
because
.
Similarly,
, because
.
If two numbers are multiplied or divided under a square root, you
can split them up. In symbols:
,