<< Chapter < Page Chapter >> Page >

Calculate f / x , f / y , and f / z for the function f ( x , y , z ) = sec ( x 2 y ) tan ( x 3 y z 2 ) .

f x = 2 x y sec ( x 2 y ) tan ( x 2 y ) 3 x 2 y z 2 sec 2 ( x 3 y z 2 ) f y = x 2 sec ( x 2 y ) tan ( x 2 y ) x 3 z 2 sec 2 ( x 3 y z 2 ) f z = −2 x 3 y z sec 2 ( x 3 y z 2 )

Got questions? Get instant answers now!

Higher-order partial derivatives

Consider the function

f ( x , y ) = 2 x 3 4 x y 2 + 5 y 3 6 x y + 5 x 4 y + 12 .

Its partial derivatives are

f x = 6 x 2 4 y 2 6 y + 5 and f y = −8 x y + 15 y 2 6 x 4 .

Each of these partial derivatives is a function of two variables, so we can calculate partial derivatives of these functions. Just as with derivatives of single-variable functions, we can call these second-order derivatives, third-order derivatives , and so on. In general, they are referred to as higher-order partial derivatives    . There are four second-order partial derivatives for any function (provided they all exist):

2 f x 2 = x [ f x ] , 2 f x y = y [ f x ] , 2 f y x = x [ f y ] , 2 f y 2 = y [ f y ] .

An alternative notation for each is f x x , f x y , f y x , and f y y , respectively. Higher-order partial derivatives calculated with respect to different variables, such as f x y and f y x , are commonly called mixed partial derivatives    .

Calculating second partial derivatives

Calculate all four second partial derivatives for the function

f ( x , y ) = x e −3 y + sin ( 2 x 5 y ) .

To calculate 2 f / d x 2 and 2 f / x y , we first calculate f / x :

f x = e −3 y + 2 cos ( 2 x 5 y ) .

To calculate 2 f / d x 2 , differentiate f / x with respect to x :

2 f x 2 = x [ f x ] = x [ e −3 y + 2 cos ( 2 x 5 y ) ] = −4 sin ( 2 x 5 y ) .

To calculate 2 f / x y , differentiate f / x with respect to y :

2 f x y = y [ f x ] = y [ e −3 y + 2 cos ( 2 x 5 y ) ] = −3 e −3 y + 10 sin ( 2 x 5 y ) .

To calculate 2 f / x y and 2 f / d y 2 , first calculate f / y :

f y = −3 x e −3 y 5 cos ( 2 x 5 y ) .

To calculate 2 f / y x , differentiate f / y with respect to x :

2 f y x = x [ f y ] = x [ −3 x e −3 y 5 cos ( 2 x 5 y ) ] = −3 e −3 y + 10 sin ( 2 x 5 y ) .

To calculate 2 f / y 2 , differentiate f / y with respect to y :

2 f y 2 = y [ f y ] = y [ −3 x e −3 y 5 cos ( 2 x 5 y ) ] = 9 x e −3 y 25 sin ( 2 x 5 y ) .
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Calculate all four second partial derivatives for the function

f ( x , y ) = sin ( 3 x 2 y ) + cos ( x + 4 y ) .

2 f x 2 = −9 sin ( 3 x 2 y ) cos ( x + 4 y ) 2 f x y = 6 sin ( 3 x 2 y ) 4 cos ( x + 4 y ) 2 f y x = 6 sin ( 3 x 2 y ) 4 cos ( x + 4 y ) 2 f y 2 = −4 sin ( 3 x 2 y ) 16 cos ( x + 4 y )

Got questions? Get instant answers now!

At this point we should notice that, in both [link] and the checkpoint, it was true that 2 f / x y = 2 f / y x . Under certain conditions, this is always true. In fact, it is a direct consequence of the following theorem.

Equality of mixed partial derivatives (clairaut’s theorem)

Suppose that f ( x , y ) is defined on an open disk D that contains the point ( a , b ) . If the functions f x y and f y x are continuous on D , then f x y = f y x .

Clairaut’s theorem guarantees that as long as mixed second-order derivatives are continuous, the order in which we choose to differentiate the functions (i.e., which variable goes first, then second, and so on) does not matter. It can be extended to higher-order derivatives as well. The proof of Clairaut’s theorem can be found in most advanced calculus books.

Two other second-order partial derivatives can be calculated for any function f ( x , y ) . The partial derivative f x x is equal to the partial derivative of f x with respect to x , and f y y is equal to the partial derivative of f y with respect to y .

Partial differential equations

In Introduction to Differential Equations , we studied differential equations in which the unknown function had one independent variable. A partial differential equation    is an equation that involves an unknown function of more than one independent variable and one or more of its partial derivatives. Examples of partial differential equations are

Questions & Answers

what are components of cells
ofosola Reply
twugzfisfjxxkvdsifgfuy7 it
Sami
58214993
Sami
what is a salt
John
the difference between male and female reproduction
John
what is computed
IBRAHIM Reply
what is biology
IBRAHIM
what is the full meaning of biology
IBRAHIM
what is biology
Jeneba
what is cell
Kuot
425844168
Sami
what is biology
Inenevwo
what is cytoplasm
Emmanuel Reply
structure of an animal cell
Arrey Reply
what happens when the eustachian tube is blocked
Puseletso Reply
what's atoms
Achol Reply
discuss how the following factors such as predation risk, competition and habitat structure influence animal's foraging behavior in essay form
Burnet Reply
cell?
Kuot
location of cervical vertebra
KENNEDY Reply
What are acid
Sheriff Reply
define biology infour way
Happiness Reply
What are types of cell
Nansoh Reply
how can I get this book
Gatyin Reply
what is lump
Chineye Reply
what is cell
Maluak Reply
what is biology
Maluak
what is vertibrate
Jeneba
what's cornea?
Majak Reply
what are cell
Achol
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 4

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Calculus volume 3' conversation and receive update notifications?

Ask