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We can now use what we have learned about curl to show that gravitational fields have no “spin.” Suppose there is an object at the origin with mass at the origin and an object with mass Recall that the gravitational force that object 1 exerts on object 2 is given by field
Show that a gravitational field has no spin.
To show that F has no spin, we calculate its curl. Let and Then,
Since the curl of the gravitational field is zero, the field has no spin.
Field models the flow of a fluid. Show that if you drop a leaf into this fluid, as the leaf moves over time, the leaf does not rotate.
Now that we understand the basic concepts of divergence and curl, we can discuss their properties and establish relationships between them and conservative vector fields.
If F is a vector field in then the curl of F is also a vector field in Therefore, we can take the divergence of a curl. The next theorem says that the result is always zero. This result is useful because it gives us a way to show that some vector fields are not the curl of any other field. To give this result a physical interpretation, recall that divergence of a velocity field v at point P measures the tendency of the corresponding fluid to flow out of P . Since the net rate of flow in vector field curl( v ) at any point is zero. Taking the curl of vector field F eliminates whatever divergence was present in F .
Let be a vector field in such that the component functions all have continuous second-order partial derivatives. Then,
By the definitions of divergence and curl, and by Clairaut’s theorem,
□
Show that is not the curl of another vector field. That is, show that there is no other vector G with
Notice that the domain of F is all of and the second-order partials of F are all continuous. Therefore, we can apply the previous theorem to F .
The divergence of F is If F were the curl of vector field G , then But, the divergence of F is not zero, and therefore F is not the curl of any other vector field.
With the next two theorems, we show that if F is a conservative vector field then its curl is zero, and if the domain of F is simply connected then the converse is also true. This gives us another way to test whether a vector field is conservative.
If is conservative, then
Since conservative vector fields satisfy the cross-partials property, all the cross-partials of F are equal. Therefore,
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