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In order to develop the wavelet expansion described in [link] , we will need the idea of an expansion set or a basis set. If we start withthe vector space of signals, S , then if any f ( t ) S can be expressed as f ( t ) = k a k φ k ( t ) , the set of functions φ k ( t ) are called an expansion set for the space S . If the representation is unique, the set is a basis. Alternatively, one could start with the expansion set or basis set and define the space S as the set of all functions that can be expressed by f ( t ) = k a k φ k ( t ) . This is called the span of the basis set. In several cases, the signal spaces that we will need are actuallythe closure of the space spanned by the basis set. That means the space contains not only all signals that can be expressed by alinear combination of the basis functions, but also the signals which are the limit of these infinite expansions. The closure of a space is usuallydenoted by an over-line.

The scaling function

In order to use the idea of multiresolution, we will start by defining the scaling function and then define the wavelet in terms of it. As describedfor the wavelet in the previous chapter, we define a set of scaling functions in terms of integer translatesof the basic scaling function by

φ k ( t ) = φ ( t - k ) k Z φ L 2 .

The subspace of L 2 ( R ) spanned by these functions is defined as

V 0 = Span k { φ k ( t ) } ¯

for all integers k from minus infinity to infinity. The over-bar denotes closure. This means that

f ( t ) = k a k φ k ( t ) for any f ( t ) V 0 .

One can generally increase the size of the subspace spanned by changing the time scale of the scaling functions. A two-dimensional family offunctions is generated from the basic scaling function by scaling and translation by

φ j , k ( t ) = 2 j / 2 φ ( 2 j t - k )

whose span over k is

V j = Span k { φ k ( 2 j t ) } ¯ = Span k { φ j , k ( t ) } ¯

for all integers k Z . This means that if f ( t ) V j , then it can be expressed as

f ( t ) = k a k φ ( 2 j t + k ) .

For j > 0 , the span can be larger since φ j , k ( t ) is narrower and is translated in smaller steps. It, therefore, can represent finerdetail. For j < 0 , φ j , k ( t ) is wider and is translated in larger steps. So these wider scaling functions can represent only coarseinformation, and the space they span is smaller. Another way to think about the effects of a change of scale is in terms of resolution. If onetalks about photographic or optical resolution, then this idea of scale is the same as resolving power.

Multiresolution analysis

In order to agree with our intuitive ideas of scale or resolution, we formulate the basic requirement of multiresolution analysis (MRA) [link] by requiring a nesting of the spanned spaces as

V - 2 V - 1 V 0 V 1 V 2 L 2

or

V j V j + 1 for all j Z

with

V - = { 0 } , V = L 2 .

The space that contains high resolution signals will contain those of lower resolution also.

Because of the definition of V j , the spaces have to satisfy a natural scaling condition

f ( t ) V j f ( 2 t ) V j + 1

which insures elements in a space are simply scaled versions of the elements in the next space. The relationship of the spanned spacesis illustrated in [link] .

The nesting of the spans of φ ( 2 j t - k ) , denoted by V j and shown in [link] and [link] and graphically illustrated in [link] , is achieved by requiring that φ ( t ) V 1 , which means that if φ ( t ) is in V 0 , it is also in V 1 , the space spanned by φ ( 2 t ) . This means φ ( t ) can be expressed in terms of a weighted sum of shifted φ ( 2 t ) as

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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Source:  OpenStax, Wavelets and wavelet transforms. OpenStax CNX. Aug 06, 2015 Download for free at https://legacy.cnx.org/content/col11454/1.6
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