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Consider an electrical circuit containing a resistor, an inductor, and a capacitor, as shown in [link] . Such a circuit is called an RLC series circuit . RLC circuits are used in many electronic systems, most notably as tuners in AM/FM radios. The tuning knob varies the capacitance of the capacitor, which in turn tunes the radio. Such circuits can be modeled by second-order, constant-coefficient differential equations.
Let denote the current in the RLC circuit and denote the charge on the capacitor. Furthermore, let L denote inductance in henrys (H), R denote resistance in ohms and C denote capacitance in farads (F). Last, let denote electric potential in volts (V).
Kirchhoff’s voltage rule states that the sum of the voltage drops around any closed loop must be zero. So, we need to consider the voltage drops across the inductor (denoted ), the resistor (denoted ), and the capacitor (denoted ). Because the RLC circuit shown in [link] includes a voltage source, which adds voltage to the circuit, we have
We present the formulas below without further development. Those of you interested in the derivation of these formulas should consult a physics text. Using Faraday’s law and Lenz’s law, the voltage drop across an inductor can be shown to be proportional to the instantaneous rate of change of current, with proportionality constant L . Thus,
Next, according to Ohm’s law, the voltage drop across a resistor is proportional to the current passing through the resistor, with proportionality constant R . Therefore,
Last, the voltage drop across a capacitor is proportional to the charge, q , on the capacitor, with proportionality constant Thus,
Adding these terms together, we get
Noting that this becomes
Mathematically, this system is analogous to the spring-mass systems we have been examining in this section.
Find the charge on the capacitor in an RLC series circuit where H, F, and V. Assume the initial charge on the capacitor is 0 C and the initial current is 9 A. What happens to the charge on the capacitor over time?
We have
The general solution to the complementary equation is
Assume a particular solution of the form where is a constant. Using the method of undetermined coefficients, we find So,
Applying the initial conditions and we find and So the charge on the capacitor is
Looking closely at this function, we see the first two terms will decay over time (as a result of the negative exponent in the exponential function). Therefore, the capacitor eventually approaches a steady-state charge of 10 C.
Find the charge on the capacitor in an RLC series circuit where H, F, and V. Assume the initial charge on the capacitor is 0 C and the initial current is 4 A.
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