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In the code that follows the image representing a broken glass is employed as texture and followed by a color interpolationand the default illumination. The shading of the surfaces, produced by means of the illumination and the colors, ismodulated in a multiplicative way by the colors of the texture. size(400,400,P3D); PImage a = loadImage("vetro.jpg");lights(); textureMode(NORMALIZED);beginShape(TRIANGLE_STRIP); texture(a);fill(240, 0, 0); vertex(40,61, 63, 0, 0); fill(240, 150, 0); vertex(340, 80, 76, 0, 1);fill(250, 250, 0); vertex(150, 176, 100, 1, 1); vertex(110, 170, 180, 1, 0);endShape();

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Texture mapping

It is evident that the mapping operations from a texture image to an object surface, of arbitrary shape, implies some formof interpolation. Similarly to what happens for colors, only the vertices that delimit the surface are mapped onto exactpoints of the texture image. What happens for the internal points has to be established in some way. Actually,Processing and OpenGL behave according to what illustrated in [link] , i.e. by bilinear interpolation: a first linear interpolation over eachboundary segment is cascaded by a linear interpolation on a scan line. If u and v exceed the limits of the texture image, the system (Processing) can assume that this isrepeated periodically and fix it to the values at the border.

A problem that occurs is that a pixel on a display does not necessarly correspond exactly to a texel. One can map morethan one texel on a pixel or, viceversa, a texel can be mapped on several pixels. The first case corresponds to adownsampling that, as seen in Sampling and Quantization , can produce aliasing. The effect of aliasing can be attenuated by means of low pass filtering ofthe texture image. The second case corresponds to upsampling, that in the frequency domain can be interpreted asincreasing the distance between spectral images.

Texture generation

Textures are not necessarely imported from images, but they can also be generated in an algorithmic fashion. This isparticularly recommended when one wants to generate regular or pseudo-random patterns. For example, the pattern of achess-board can be generated by means of the code PImage textureImg = loadImage("vetro.jpg"); // dummy image colorMode(RGB,1);int biro = 0; int bbiro = 0;int scacco = 5; for (int i=0; i<textureImg.width; i+=scacco) { bbiro = (bbiro + 1)%2; biro = bbiro;for (int j=0; j<textureImg.height; j+=scacco) { for (int r=0; r<scacco; r++) for (int s=0; s<scacco; s++) textureImg.set(i+r,j+s, color(biro));biro = (biro + 1)%2; }} image(textureImg, 0, 0);

The use of the function random, combined with filters of various type, allows a wide flexibility in the production oftextures. For example, the pattern represented in [link] was obtained from a modification of the code generating the chess-board. In particular, we added theline scacco=floor(2+random(5)); within the outer for , and applied an averaging filter.

Algorithmically-generated pattern

How could one modify the code [link] in order to make the breaks in the glass more evident?

It is sufficient to consider only a piece of the texture, with calls of the type vertex(150, 176, 0.3, 0.3);

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The excercise consists in modifying the code of the generator of the chess-board in [link] in order to generate the texture [link] .

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This exercise consists in running and analyzing the following code. Try then to vary the dimensions of the smallsquares and the filtering type. size(200, 100, P3D);PImage textureImg = loadImage("vetro.jpg"); // dummy image colorMode(RGB,1);int biro = 0; int bbiro = 0;int scacco = 5; for (int i=0; i<textureImg.width; i+=scacco) { // scacco=floor(2+random(5));bbiro = (bbiro + 1)%2; biro = bbiro; for (int j=0; j<textureImg.height; j+=scacco) { for (int r=0; r<scacco; r++) for (int s=0; s<scacco; s++) textureImg.set(i+r,j+s, color(biro));biro = (biro + 1)%2; }} image(textureImg, 0, 0);textureMode(NORMALIZED); beginShape(QUADS);texture(textureImg); vertex(20, 20, 0, 0);vertex(80, 25, 0, 0.5); vertex(90, 90, 0.5, 0.5);vertex(20, 80, 0.5, 0); endShape();// ------ filtering ------- PImage tImg = loadImage("vetro.jpg"); // dummy imagefloat val = 1.0/9.0; float[][] kernel = { {val, val, val},{val, val, val}, {val, val, val} };int n2 = 1; int m2 = 1;colorMode(RGB,255); // Convolve the imagefor(int y=0; y<textureImg.height; y++) { for(int x=0; x<textureImg.width/2; x++) { float sum = 0;for(int k=-n2; k<=n2; k++) { for(int j=-m2; j<=m2; j++) { // Reflect x-j to not exceed array boundaryint xp = x-j; int yp = y-k;if (xp<0) { xp = xp + textureImg.width;} else if (x-j>= textureImg.width) { xp = xp - textureImg.width;} // Reflect y-k to not exceed array boundaryif (yp<0) { yp = yp + textureImg.height;} else if (yp>= textureImg.height) { yp = yp - textureImg.height;} sum = sum + kernel[j+m2][k+n2] * red(textureImg.get(xp,yp)); }} tImg.set(x,y, color(int(sum)));} }translate(100, 0);beginShape(QUADS); texture(tImg);vertex(20, 20, 0, 0); vertex(80, 25, 0, 0.5);vertex(90, 90, 0.5, 0.5); vertex(20, 80, 0.5, 0);endShape();

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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
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Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
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Source:  OpenStax, Media processing in processing. OpenStax CNX. Nov 10, 2010 Download for free at http://cnx.org/content/col10268/1.14
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