<< Chapter < Page
  Digital signal processing - dsp     Page 11 / 14
Chapter >> Page >
Figure 5. Filtering in the frequency domain.
missing image

Compare the results

The basic plotting format of Figure 5 is the same as Figure 4 .

Compare Figure 5 With Figure 4

The first difference to note between the two figures is that I moved the impulse in the input time series in the topmost plot sixteen samples further tothe right in Dsp038 .

(This has no impact on the final result, which you can verify by modifying the program to move the impulse to a different position and thencompiling and running the modified program.)

Compare the bandwidth of the pass band

The second difference to note is shown in the modified amplitude spectrum in the fourth plot in the two figures. The bandwidth of the pass band issignificantly narrower in Figure 5 than in Figure 4 . Also, the pass band in Figure 4 extends all the way down to zero frequency, while Figure 5 eliminates all energy below a frequency of three thirty-seconds of the sampling frequency.

Waveforms of filtered impulse

Finally, note the waveforms of the two filtered impulses. The overall amplitude of the filtered impulse in Figure 5 is less than in Figure 4 , simply because it contains less total energy. In addition, the filtered impulse in Figure 5 is broader than the filtered impulse in Figure 4 . This is because it has a narrower bandwidth.

(Pulses that are narrow in terms of time duration require a wider bandwidth than pulses that have a longer time duration. The time duration ofthe pulse tends to be inversely related to the required bandwidth for the pulse.)

Run the programs

I encourage you to copy, compile, and run the programs provided in this module. Experiment with them, making changes and observing the results of yourchanges.

Create more complex experiments. For example, use more complex input time series when experimenting with frequency filtering. Apply differentmodifications to the complex spectrum when experimenting with frequency filtering.

Most of all enjoy yourself and learn something in the process.

Summary

This module illustrates and explains forward and inverse Fourier transforms using both DFT and FFT algorithms.

The module also illustrates and explains the implementation of frequency filtering by modifying the complex spectrum in the frequency domain and thentransforming the modified complex spectrum back into the time domain.

Complete program listings

Complete listings of the programs discussed in this module are provided below.

Listings for other programs mentioned in the module, such as Graph03 and Graph06 , are provided in other modules. Those modules are identified in the text of this module.

Listing 14. Dsp035.java.
import java.util.*; class Dsp035 implements GraphIntfc01{final double pi = Math.PI; int len = 256;double[] timeDataIn = new double[len]; double[]realSpect = new double[len];double[] imagSpect = new double[len]; double[]angle = new double[len];//unuseddouble[] magnitude = new double[len]; double[]timeDataOut = new double[len];int zero = 0; public Dsp035(){//constructor//Create the raw data pulses timeDataIn[0]= 0; timeDataIn[1]= 50; timeDataIn[2]= 75; timeDataIn[3]= 80; timeDataIn[4]= 75; timeDataIn[5]= 50; timeDataIn[6]= 25; timeDataIn[7]= 0; timeDataIn[8]= -25; timeDataIn[9]= -50; timeDataIn[10]= -75; timeDataIn[11]= -80; timeDataIn[12]= -60; timeDataIn[13]= -40; timeDataIn[14]= -26; timeDataIn[15]= -17; timeDataIn[16]= -11; timeDataIn[17]= -8; timeDataIn[18]= -5; timeDataIn[19]= -3; timeDataIn[20]= -2; timeDataIn[21]= -1; timeDataIn[240]= 80; timeDataIn[241]= 80; timeDataIn[242]= 80; timeDataIn[243]= 80; timeDataIn[244]= -80; timeDataIn[245]= -80; timeDataIn[246]= -80; timeDataIn[247]= -80; timeDataIn[248]= 80; timeDataIn[249]= 80; timeDataIn[250]= 80; timeDataIn[251]= 80; timeDataIn[252]= -80; timeDataIn[253]= -80; timeDataIn[254]= -80; timeDataIn[255]= -80; //Create raw data sinusoidfor(int x = len/3;x<3*len/4;x++){ timeDataIn[x]= 80.0 * Math.sin( 2*pi*(x)*1.0/20.0);}//end for loop //Compute DFT of the time data and save it in// the output arrays. ForwardRealToComplex01.transform(timeDataIn,realSpect, imagSpect,angle, magnitude,zero, 0.0,1.0); //Compute inverse DFT of spectral data and// save output time data in output array InverseComplexToReal01.inverseTransform(realSpect, imagSpect,timeDataOut); }//end constructor//-------------------------------------------// //The following six methods are required by the// interface named GraphIntfc01. public int getNmbr(){//Return number of curves to plot. Must not // exceed 5.return 5; }//end getNmbr//-------------------------------------------// public double f1(double x){int index = (int)Math.round(x); if(index<0 || index>timeDataIn.length-1){ return 0;}else{ return timeDataIn[index]; }//end else}//end function //-------------------------------------------//public double f2(double x){ int index = (int)Math.round(x);if(index<0 || index>realSpect.length-1){ return 0;}else{ //scale for convenient viewingreturn 5*realSpect[index];}//end else }//end function//-------------------------------------------// public double f3(double x){int index = (int)Math.round(x); if(index<0 || index>imagSpect.length-1){ return 0;}else{ //scale for convenient viewingreturn 5*imagSpect[index];}//end else }//end function//-------------------------------------------// public double f4(double x){int index = (int)Math.round(x); if(index<0 || index>magnitude.length-1){ return 0;}else{ //scale for convenient viewingreturn 5*magnitude[index];}//end else }//end function//-------------------------------------------// public double f5(double x){int index = (int)Math.round(x); if(index<0 || index>timeDataOut.length-1){ return 0;}else{ return timeDataOut[index]; }//end else}//end function }//end sample class Dsp035

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Digital signal processing - dsp' conversation and receive update notifications?

Ask