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We examine interference from two coherent sources.

Interference

Waves on a pond:

Think of when you drop a pebble into a pond, you will see circular waves eminate from the point where you dropped the pebble.

When you drop two pebbles side by side you will see a much more complicatedpattern:

Likewise with electromagnetic waves, you can get interesting interference phenomenawhen waves eminate from two point sources.

Two point sources

Lets take a particular example of two point sources separated by a distance d. The waves emitted by point source are spherical and thus can be written E = E 0 r cos ( k r ω t ) To make the problem easier we will make the k 's the same for the two sources. Also lets set the E 0 's to be the same as well.

The the only difference in the waves will be the r 's, that is E 1 = E 0 r 1 cos ( k r 1 ω t ) E 2 = E 0 r 2 cos ( k r 2 ω t ) Now there is a slightly subtle point here that is important to understand. In the denominator it is sufficient to say that r 1 r 2 and just call it r . We assume that we are far enough away that the differences between r 1 and r 2 are too small to matter. However this is not true in the argument of the harmonic function. There, very small differences between r 1 and r 2 can have a big effect. So lets define r 1 = r 2 = R I ( E 0 R cos ( k r 1 ω t ) + E 0 R cos ( k r 2 ω t ) ) 2 T = E 0 2 R 2 cos 2 ( k r 1 ω t ) T + E 0 2 R 2 cos 2 ( k r 2 ω t ) T    + 2 E 0 2 R 2 cos ( k r 1 ω t ) cos ( k r 2 ω t ) T = 1 2 E 0 2 R 2 + 1 2 E 0 2 R 2 + + 2 E 0 2 R 2 cos ( k r 1 ω t ) cos ( k r 2 ω t ) T Now to evaluate the final term we use cos ( θ φ ) = cos θ cos φ + sin θ sin φ and write So we have I 1 2 E 0 2 R 2 + 1 2 E 0 2 R 2 + 2 E 0 2 R 2 1 2 cos k Δ r = 1 R 2 ( E 0 2 + E 0 2 cos k Δ r ) = 1 R 2 E 0 2 ( 1 + cos k Δ r )

Clearly I will be a maximum when the cosine is = +1 k Δ r = 2 n π    n = 0 , 1 , 2 2 π λ Δ r = 2 n π Δ r = n λ There will be a minimum when the cosine is = -1 k Δ r = n π    n = 1 , 3 , 5 Δ r = n λ 2    n = 1 , 3 , 5 So you get light and dark bands which are called interference fringes.To reiterate; we have two rays of light eminating from two point sources. Wehave looked at the combined wave at some point, a distance r 1 from the first source and a distance from the second source. In that case we find that the intensity is proportional to 1 R 2 E 0 2 ( 1 + cos k Δ r ) . To make things easier we can redefine E 0 to be the amplitude of the waves at the point under consideration, that is I = ε 0 c E 0 2 ( 1 + cos k Δ r ) . Or we can say I 0 = ε c E 0 2 / 2 and write I = 2 I 0 ( 1 + cos k Δ r ) .

Say we place a screen a distance S away from the two sources:

In this case we see that Δ r = d sin θ So we have maxima at Δ r = n λ = d sin θ . The angle between two maxima is given by sin θ n + 1 sin θ n = λ d or for small θ Δ θ = λ d Notice how when the sources are moved far apart the effect maxima become very closetogether so the screen appears to be uniformly illuminated. If a screen is placed a distance S away the maxima on the screen will occur such that d sin θ = n λ but in the small angle limit sin θ = tan θ = y S which implies y = n λ S d likewise minima will occur at y = n λ S 2 d    n = 1 , 3 , 5 using cos θ = 2 cos 2 θ 2 1 we can rewrite I = 2 I 0 ( 1 + cos k Δ r ) as I = 4 I 0 cos 2 k Δ r 2

Young's double slit

Young's double slit.is an excellent example of two source interference. The equations for this are what we worked out for two sources above. Interferenceis an excellent way to measure fine position changes. Small changes in Δ r make big observable changes in the interference fringes.

Michelson interferometer

A particularly useful example of using interference is the Michelson interferometer. This can be used to measure the speed of light in a medium,measure the fine position of something, and was used to show that the speed of light is a constant in all directions.

When Δ r , the path length difference in the two arms is Δ r = n λ then the rays of light in the traveling down the center of the apparatus will interfere constructively. As you move off axis the light travels slightlydifferent lengths and so you get rings of interference patterns. If you have set up the apparatus so that Δ r = n λ and then move one of the mirrors a quarter wavelength then Δ r = n λ + 1 2 λ and you get destructive interference of the central rays. Thus you can easily position things to a fraction of a micron with such a set up.

What really matters is the change in the optical pathlength. For example you could introduce a medium in one of the paths that has a different index ofrefraction, or different velocity of light. This will change the optical pathlength and change the interference at the observer. Thus you can measurethe velocity of the light in the introduced medium.

Michelson and Morely used this technique to try to determine if the speed of light is different in different directions. They put the whole apparatus on arotating table and then looked for changes in the interference fringes as it rotated. They saw no changes. In fact they went so far as to wait to see whathappened as the earth rotated and orbited and saw no changes. They thus concluded that the speed of light was the same in all directions (which nobodyat the time believed, even though that is the conclusion you draw from Maxwell's equations.)

Ring gyroscope

Another application of interference is a a gyroscope, ie. as device to measure rotations.

If the apparatus is rotating, then the pathlengths are different in different directions and so you can use the changes in the interference patterns tomeasure rotations. This is in fact how gyroscopes are implemented in modern aircraft.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Waves and optics. OpenStax CNX. Nov 17, 2005 Download for free at http://cnx.org/content/col10279/1.33
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