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If the sample qualifies as valid, we must find the ellipse which satisfies the condition that the sample distance equals the distance to the reflection surface and back. Using ellipse properties, we can see that the points of this ellipse can be found relative either the source or receiver.The equation for the ellipse in polar coordinates (r,phi) from one focus is:

r a ( 1 - e 2 ) e cos ( phi ) + 1

where e is the eccentricity of the ellipse, a is the semi-major axes, and c is the distance of the focus to the center of the ellipse. The geometry for finding a and c is shown below:

Ellipse geometry.

We know c as the distance between the source and receiver divided by 2. a can be found by realizing that:

b 2 a 2 - c 2

b can be obtained since the hypotenuse of each right triangle is equal to half the sample distance. A little trigonometry takes care of finding b :

theta acos ( c hypotenuse )
b hypotenuse * sin ( theta )

Eccentricity e is simply defined as:

e c a

We then plug all this into Equation (6) and get a vector of radii for all phi between pi and 2*pi (the negative half of the unit circle).

This vector is mapped to the image grid via the matlab command pol2cart and the shifted by c to bring the ellipse into line with the focii (source and receiver).

Finally, the value of the time sample is then added to these grid coordinates. The process is repeated for each source-receiver time vector.

Time comparison

Both methods require treating each of the 4096 vectors separately and traversing the vectors one by one. Therefore, we can talk about efficiency in terms of the time required to process one vector and extrapolate this to total processing time. Without any optimizations, both methods take several seconds to process one vector, which means that total process time is on the order of 5-10 hours. So how can we reduce these times? Well, one obvious answer would be to use a different computing simulator or work with a language more optimized for this type of processing. However, for our purposes, let’s only consider optimizations to the actual algorithms.

For method one, the main factor we can control is the size of the grid. We may greatly reduce our processing time by simply searching a smaller grid. The idea is to traverse the entire grid for the first few vectors and then to only traverse the areas where the magnitude is greater than some threshold. It is possible, in this way, to decrease the area by a factor of 2-10 and thus improve the speed.

For method two, we set a threshold value and only consider time samples above this value. This is helpful in eliminating all of the zero values in the early part of the time vectors that occur before any pulse returns. We must be careful however in this optimization because if we set the threshold too high, we will be hurting our resolution and/or creating noise in the graph.

Algorithm timing comparison (approx. times)
Experiment Algorithm
Method 1 Method 2
Mountain (Full Algorithm) 10-12 sec 5 sec
Mountain (Optimized) 3-4 sec 1-2 sec
ELEC (Optimized) 5-6 sec 3-4 sec

Resolution comparison

Here are two pictures of the same image reconstructed using each method

Image from Method 1
Image from Method 2

As you can see, Method 1 shows details much more clearly because it uses a linear interpolation formula, while Method 2 rounds off the ellipse coordinates to fit them to the grid. This means that method one should be more accurate and should show less error from the discrete nature of the samples. Method 2 is faster, but method 1 shows higher resolution.

You can download copies of the matlab code for method 1 , the optimizing wrapper for method 1 and method 2 .

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
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emma Reply
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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what are the types of wave
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answer
Magreth
progressive wave
Magreth
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
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Source:  OpenStax, Seismic imaging. OpenStax CNX. Dec 16, 2004 Download for free at http://cnx.org/content/col10251/1.1
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