To prove that the Vandermonde determinant is equal to the product above, we can apply row and column operations to compute the determinant:
where in the last step we are subtracting from each column multiples of earlier columns. The desired formula for the Vandermonde determinant then follows by induction on
.
Exercises
- If
are non-constant polynomials over the complex numbers, show that
and
have a common root in
if and only if
.
[Hint: Use the “fundamental theorem of algebra”: the fact that any non-constant polynomial in
factors completely into linear factors.]
- If
, where
and
, then the
discriminant of
is defined to be
Prove that
has a multiple factor (that is,
is divisible by
for some non-constant
) if and only if
.
-
- Compute the discriminant of the polynomial
for
- Compute the discriminant of the polynomial
for
.
- An alternative definition of the discriminant of a polynomial
of degree
is
where
are the roots of
, counted with multiplicities, i.e.
.
- Show that
doesn't depend on the choice of ordering on the roots
.
- Show that
.
- For
, show that
.
- Let
have degrees
and
. Show that if the
Sylvester matrix has rank
, then
and
share a common linear factor, but not a common quadratic factor.
Quotient rings and the tjurina number
Starting with the integers
, if we fix a positive integer
, we can construct the integers modulo
as follows: we let
be
the set of possible remainders upon dividing an integer by
. To add or multiply
, we add or multiply them in
and then take the remainder upon division by
, e.g. we would write
, and the product of
and
in
would be
.