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The same theorem is true for vector fields in a plane.
Since a conservative vector field is the gradient of a scalar function, the previous theorem says that for any scalar function In terms of our curl notation, This equation makes sense because the cross product of a vector with itself is always the zero vector. Sometimes equation is simplified as
Let be a vector field in space on a simply connected domain. If then F is conservative.
Since we have that and Therefore, F satisfies the cross-partials property on a simply connected domain, and [link] implies that F is conservative.
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The same theorem is also true in a plane. Therefore, if F is a vector field in a plane or in space and the domain is simply connected, then F is conservative if and only if
Use the curl to determine whether is conservative.
Note that the domain of F is all of which is simply connected ( [link] ). Therefore, we can test whether F is conservative by calculating its curl.
The curl of F is
Thus, F is conservative.
We have seen that the curl of a gradient is zero. What is the divergence of a gradient? If is a function of two variables, then We abbreviate this “double dot product” as This operator is called the Laplace operator , and in this notation Laplace’s equation becomes Therefore, a harmonic function is a function that becomes zero after taking the divergence of a gradient.
Similarly, if is a function of three variables then
Using this notation we get Laplace’s equation for harmonic functions of three variables:
Harmonic functions arise in many applications. For example, the potential function of an electrostatic field in a region of space that has no static charge is harmonic.
Is it possible for to be the potential function of an electrostatic field that is located in a region of free of static charge?
If were such a potential function, then would be harmonic. Note that and and so Therefore, is not harmonic and cannot represent an electrostatic potential.
Is it possible for function to be the potential function of an electrostatic field located in a region of free of static charge?
Yes
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