11.1 Graphs, trigonometric identities, and solving trigonometric  (Page 2/12)

Functions of the form $y=tan\left(k\theta \right)$

In the equation, $y=tan\left(k\theta \right)$ , $k$ is a constant and has different effects on the graph of the function. The general shape of the graph of functions of this form is shown in [link] for the function $f\left(\theta \right)=tan\left(2\theta \right)$ .

Functions of the form $y=tan\left(k\theta \right)$

On the same set of axes, plot the following graphs:

1. $a\left(\theta \right)=tan0,5\theta$
2. $b\left(\theta \right)=tan1\theta$
3. $c\left(\theta \right)=tan1,5\theta$
4. $d\left(\theta \right)=tan2\theta$
5. $e\left(\theta \right)=tan2,5\theta$

Use your results to deduce the effect of $k$ .

You should have found that, once again, the value of $k$ affects the periodicity (i.e. frequency) of the graph. As $k$ increases, the graph is more tightly packed. As $k$ decreases, the graph is more spread out. The period of the tan graph is given by $\frac{{180}^{\circ }}{k}$ .

These different properties are summarised in [link] .

$k>0$	$k<0$

Domain and range

For $f\left(\theta \right)=tan\left(k\theta \right)$ , the domain of one branch is $\{\theta :\theta \in (-\frac{{90}^{\circ }}{k},\frac{{90}^{\circ }}{k})\}$ because the function is undefined for $\theta =-\frac{{90}^{\circ }}{k}$ and $\theta =\frac{{90}^{\circ }}{k}$ .

The range of $f\left(\theta \right)=tan\left(k\theta \right)$ is $\left\{f\right(\theta ):f(\theta )\in (-\infty ,\infty \left)\right\}$ .

Intercepts

For functions of the form, $y=tan\left(k\theta \right)$ , the details of calculating the intercepts with the $x$ and $y$ axis are given.

There are many $x$ -intercepts; each one is halfway between the asymptotes.

The $y$ -intercept is calculated as follows:

Asymptotes

The graph of $tank\theta$ has asymptotes because as $k\theta$ approaches ${90}^{\circ }$ , $tank\theta$ approaches infinity. In other words, there is no defined value of the function at the asymptote values.

Functions of the form $y=sin(\theta +p)$

In the equation, $y=sin(\theta +p)$ , $p$ is a constant and has different effects on the graph of the function. The general shape of the graph of functions of this form is shown in [link] for the function $f\left(\theta \right)=sin(\theta +{30}^{\circ })$ .

Functions of the form $y=sin(\theta +p)$

On the same set of axes, plot the following graphs:

1. $a\left(\theta \right)=sin(\theta -{90}^{\circ })$
2. $b\left(\theta \right)=sin(\theta -{60}^{\circ })$
3. $c\left(\theta \right)=sin\theta$
4. $d\left(\theta \right)=sin(\theta +{90}^{\circ })$
5. $e\left(\theta \right)=sin(\theta +{180}^{\circ })$

Use your results to deduce the effect of $p$ .

You should have found that the value of $p$ affects the position of the graph along the $y$ -axis (i.e. the $y$ -intercept) and the position of the graph along the $x$ -axis (i.e. the phase shift ). The $p$ value shifts the graph horizontally. If $p$ is positive, the graph shifts left and if $p$ is negative tha graph shifts right.

These different properties are summarised in [link] .

$p>0$	$p<0$

Domain and range

For $f\left(\theta \right)=sin(\theta +p)$ , the domain is $\{\theta :\theta \in \mathbb{R}\}$ because there is no value of $\theta \in \mathbb{R}$ for which $f\left(\theta \right)$ is undefined.

The range of $f\left(\theta \right)=sin(\theta +p)$ is $\left\{f\right(\theta ):f(\theta )\in [-1,1\left]\right\}$ .

Intercepts

For functions of the form, $y=sin(\theta +p)$ , the details of calculating the intercept with the $y$ axis are given.

The $y$ -intercept is calculated as follows: set $\theta =0^{\circ }$

Functions of the form $y=cos(\theta +p)$

In the equation, $y=cos(\theta +p)$ , $p$ is a constant and has different effects on the graph of the function. The general shape of the graph of functions of this form is shown in [link] for the function $f\left(\theta \right)=cos(\theta +{30}^{\circ })$ .