Comparing Strings for equality in java What Yasser Ibrahim @Jobilize

Author: Yasser Ibrahim

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Question 100 / 297: What is the result of compiling and running the following program?

public class Tester {

public static void main(String[] args) {
		
		String a = "javachamp";
		String b = "javachamp";
		String c = new String("javachamp");
		
		System.out.print(a==b);
		System.out.print(a==c);
		System.out.print(b.equals(c));
		System.out.print(b.equals(a));

	}
}

A Compilation error

B falsefalsetruetrue

C truetruetruetrue

D truefalsetruetrue

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Explanation:

== checks if two references are referring to the same object (physical memory location)

equals() checks if the two objects have the same value

a and b both refer to the same string literal, which was created in a special memory area called "String constant pool". Therefor a==b and b.equals(a) return true.

While c is a reference to an object created in the heap by the virtue of using the keyword "new". Th object is created in the heap with a new memory location, therefor == fails to succeed when comparing a==c or b==c.

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