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Calculus volume 1
Derivatives
The chain rule
Taking a derivative using leibniz’s notation, example 1
Find the derivative of
y
=
(
x
3
x
+
2
)
5
.
First, let
u
=
x
3
x
+
2
. Thus,
y
=
u
5
. Next, find
d
u
d
x and
d
y
d
u
. Using the quotient rule,
d
u
d
x
=
2
(
3
x
+
2
)
2
and
d
y
d
u
=
5
u
4
.
Finally, we put it all together.
d
y
d
x
=
d
y
d
u
·
d
u
d
x
Apply the chain rule.
=
5
u
4
·
2
(
3
x
+
2
)
2
Substitute
d
y
d
u
=
5
u
4
and
d
u
d
x
=
2
(
3
x
+
2
)
2
.
=
5
(
x
3
x
+
2
)
4
·
2
(
3
x
+
2
)
2
Substitute
u
=
x
3
x
+
2
.
=
10
x
4
(
3
x
+
2
)
6
Simplify.
It is important to remember that, when using the Leibniz form of the chain rule, the final answer must be expressed entirely in terms of the original variable given in the problem.
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Taking a derivative using leibniz’s notation, example 2
Find the derivative of
y
=
tan
(
4
x
2
−
3
x
+
1
)
.
First, let
u
=
4
x
2
−
3
x
+
1
. Then
y
=
tan
u
. Next, find
d
u
d
x and
d
y
d
u
:
d
u
d
x
=
8
x
−
3
and
d
y
d
u
=
sec
2
u
.
Finally, we put it all together.
d
y
d
x
=
d
y
d
u
·
d
u
d
x
Apply the chain rule.
=
sec
2
u
·
(
8
x
−
3
)
Use
d
u
d
x
=
8
x
−
3
and
d
y
d
u
=
sec
2
u
.
=
sec
2
(
4
x
2
−
3
x
+
1
)
·
(
8
x
−
3
)
Substitute
u
=
4
x
2
−
3
x
+
1
.
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Use Leibniz’s notation to find the derivative of
y
=
cos
(
x
3
)
. Make sure that the final answer is expressed entirely in terms of the variable
x
.
d
y
d
x
=
−3
x
2
sin
(
x
3
)
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Key concepts
The chain rule allows us to differentiate compositions of two or more functions. It states that for
h
(
x
)
=
f
(
g
(
x
)
)
,
h
′
(
x
)
=
f
′
(
g
(
x
)
)
g
′
(
x
)
.
In Leibniz’s notation this rule takes the form
d
y
d
x
=
d
y
d
u
·
d
u
d
x
.
We can use the chain rule with other rules that we have learned, and we can derive formulas for some of them.
The chain rule combines with the power rule to form a new rule:
If
h
(
x
)
=
(
g
(
x
)
)
n
,
then
h
′
(
x
)
=
n
(
g
(
x
)
)
n
−
1
g
′
(
x
)
.
When applied to the composition of three functions, the chain rule can be expressed as follows: If
h
(
x
)
=
f
(
g
(
k
(
x
)
)
)
, then
h
′
(
x
)
=
f
′
(
g
(
k
(
x
)
)
g
′
(
k
(
x
)
)
k
′
(
x
)
.
Key equations
The chain rule
h
′
(
x
)
=
f
′
(
g
(
x
)
)
g
′
(
x
)
The power rule for functions
h
′
(
x
)
=
n
(
g
(
x
)
)
n
−
1
g
′
(
x
)
For the following exercises, given
y
=
f
(
u
) and
u
=
g
(
x
)
, find
d
y
d
x by using Leibniz’s notation for the chain rule:
d
y
d
x
=
d
y
d
u
d
u
d
x
.
For each of the following exercises,
decompose each function in the form
y
=
f
(
u
) and
u
=
g
(
x
)
, and
find
d
y
d
x as a function of
x
.
For the following exercises, find
d
y
d
x for each function.
[T] Find the equation of the tangent line to
y
=
(
3
x
+
1
x
)
2 at the point
(
1
,
16
)
. Use a calculator to graph the function and the tangent line together.
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[T] Find an equation of the line that is normal to
g
(
θ
)
=
sin
2
(
π
θ
) at the point
(
1
4
,
1
2
)
. Use a calculator to graph the function and the normal line together.
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For the following exercises, use the information in the following table to find
h
′
(
a
) at the given value for
a
.
x
f
(
x
)
f
′
(
x
)
g
(
x
)
g
′
(
x
)
0
2
5
0
2
1
1
−2
3
0
2
4
4
1
−1
3
3
−3
2
3
[T] The position function of a freight train is given by
s
(
t
)
=
100
(
t
+
1
)
−2
, with
s in meters and
t in seconds. At time
t
=
6 s, find the train’s
velocity and
acceleration.
Using a. and b. is the train speeding up or slowing down?
a.
−
200
343 m/s, b.
600
2401 m/s
2 , c. The train is slowing down since velocity and acceleration have opposite signs.
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[T] A mass hanging from a vertical spring is in simple harmonic motion as given by the following position function, where
t is measured in seconds and
s is in inches:
s
(
t
)
=
−3
cos
(
π
t
+
π
4
)
.
Determine the position of the spring at
t
=
1.5 s.
Find the velocity of the spring at
t
=
1.5 s. Got questions? Get instant answers now!
[T] The total cost to produce
x boxes of Thin Mint Girl Scout cookies is
C dollars, where
C
=
0.0001
x
3
−
0.02
x
2
+
3
x
+
300
. In
t weeks production is estimated to be
x
=
1600
+
100
t boxes.
Find the marginal cost
C
′
(
x
)
.
Use Leibniz’s notation for the chain rule,
d
C
d
t
=
d
C
d
x
·
d
x
d
t
, to find the rate with respect to time
t that the cost is changing.
Use b. to determine how fast costs are increasing when
t
=
2 weeks. Include units with the answer.
a.
C
′
(
x
)
=
0.0003
x
2
−
0.04
x
+
3 b.
d
C
d
t
=
100
·
(
0.0003
x
2
−
0.04
x
+
3
) c. Approximately $90,300 per week
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[T] The formula for the area of a circle is
A
=
π
r
2
, where
r is the radius of the circle. Suppose a circle is expanding, meaning that both the area
A and the radius
r (in inches) are expanding.
Suppose
r
=
2
−
100
(
t
+
7
)
2 where
t is time in seconds. Use the chain rule
d
A
d
t
=
d
A
d
r
·
d
r
d
t to find the rate at which the area is expanding.
Use a. to find the rate at which the area is expanding at
t
=
4 s. Got questions? Get instant answers now!
[T] The formula for the volume of a sphere is
S
=
4
3
π
r
3
, where
r (in feet) is the radius of the sphere. Suppose a spherical snowball is melting in the sun.
Suppose
r
=
1
(
t
+
1
)
2
−
1
12 where
t is time in minutes. Use the chain rule
d
S
d
t
=
d
S
d
r
·
d
r
d
t to find the rate at which the snowball is melting.
Use a. to find the rate at which the volume is changing at
t
=
1 min.
a.
d
S
d
t
=
−
8
π
r
2
(
t
+
1
)
3 b. The volume is decreasing at a rate of
−
π
36 ft
3 /min.
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[T] The daily temperature in degrees Fahrenheit of Phoenix in the summer can be modeled by the function
T
(
x
)
=
94
−
10
cos
[
π
12
(
x
−
2
)
]
, where
x is hours after midnight. Find the rate at which the temperature is changing at 4 p.m.
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[T] The depth (in feet) of water at a dock changes with the rise and fall of tides. The depth is modeled by the function
D
(
t
)
=
5
sin
(
π
6
t
−
7
π
6
)
+
8
, where
t is the number of hours after midnight. Find the rate at which the depth is changing at 6 a.m.
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Source:
OpenStax, Calculus volume 1. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11964/1.2
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