1.10 Systems of measurement  (Page 4/13)

Solution

1. ⓐ We will convert liters to kiloliters. In [link] , we see that $1\text{kiloliter}=\text{1,000 liters.}$
   

   	$\text{350 L}$
   Multiply by 1, writing 1 as a fraction relating liters to kiloliters.	$\text{350 L}\cdot \frac{\text{1 kL}}{\text{1,000 L}}$
   Simplify.	$350\cancel{\text{L}}\cdot \frac{\text{1 kL}}{\mathrm{1,000}\cancel{\text{L}}}$
   	$\text{0.35 kL}$

   
   
   
2. ⓑ We will convert liters to milliliters. From [link] we see that $\text{1 liter}=\text{1,000 milliliters.}$
   

   Multiply by 1, writing 1 as a fraction relating liters to milliliters.
   Simplify.
   Move the decimal 3 units to the right.

Solution

We can convert both measurements to either centimeters or meters. Since meters is the larger unit, we will subtract the lengths in meters. We convert 85 centimeters to meters by moving the decimal 2 places to the left.

Ryland is $\text{0.75 m}$ taller than his brother.

Solution

We will find the amount of olive oil in millileters then convert to liters.

$\begin{array}{cccc}& & & \hfill \text{Triple 150 mL}\hfill \\ \text{Translate to algebra.}\hfill & & & \hfill 3·150\text{mL}\hfill \\ \text{Multiply.}\hfill & & & \hfill \text{450 mL}\hfill \\ \text{Convert to liters.}\hfill & & & \hfill 450·\frac{0.001\text{L}}{1\text{mL}}\hfill \\ \text{Simplify.}\hfill & & & \hfill \text{0.45 L}\hfill \\ & & & \hfill \text{Dena needs 0.45 liters of olive oil.}\hfill \end{array}$