4.6 Find the equation of a line  (Page 6/7)

slope 3 and y -intercept $\left(0,5\right)$

slope 4 and y -intercept $\left(0,1\right)$

slope 6 and y -intercept $\left(0,\mathrm{-4}\right)$

slope 8 and y -intercept $\left(0,\mathrm{-6}\right)$

slope $\mathrm{-1}$ and y -intercept $\left(0,3\right)$

slope $\mathrm{-1}$ and y -intercept $\left(0,7\right)$

slope $\mathrm{-2}$ and y -intercept $\left(0,\mathrm{-3}\right)$

slope $\mathrm{-3}$ and y -intercept $\left(0,\mathrm{-1}\right)$

slope $\frac{3}{5}$ and y -intercept $\left(0,\mathrm{-1}\right)$

slope $\frac{1}{5}$ and y -intercept $\left(0,\mathrm{-5}\right)$

slope $-\frac{3}{4}$ and y -intercept $\left(0,\mathrm{-2}\right)$

slope $-\frac{2}{3}$ and y -intercept $\left(0,\mathrm{-3}\right)$

slope 0 and y -intercept $\left(0,\mathrm{-1}\right)$

slope 0 and y -intercept $\left(0,2\right)$

slope $\mathrm{-3}$ and y -intercept $\left(0,0\right)$

slope $\mathrm{-4}$ and y -intercept $\left(0,0\right)$

$m=\frac{5}{8}$ , point $\left(8,3\right)$

$m=\frac{3}{8}$ , point $\left(8,2\right)$

$m=\frac{1}{6}$ , point $\left(6,1\right)$

$m=\frac{5}{6}$ , point $\left(6,7\right)$

$m=-\frac{3}{4}$ , point $\left(8,\mathrm{-5}\right)$

$m=-\frac{3}{5}$ , point $\left(10,\mathrm{-5}\right)$

$m=-\frac{1}{4}$ , point $\left(\mathrm{-12},\mathrm{-6}\right)$

$m=-\frac{1}{3}$ , point $\left(\mathrm{-9},\mathrm{-8}\right)$

Horizontal line containing $\left(\mathrm{-2},5\right)$

Horizontal line containing $\left(\mathrm{-1},4\right)$

Horizontal line containing $\left(\mathrm{-2},\mathrm{-3}\right)$

Horizontal line containing $\left(\mathrm{-1},\mathrm{-7}\right)$

$m=-\frac{3}{2}$ , point $\left(\mathrm{-4},\mathrm{-3}\right)$

$m=-\frac{5}{2}$ , point $\left(\mathrm{-8},\mathrm{-2}\right)$

$m=\mathrm{-7}$ , point $\left(\mathrm{-1},\mathrm{-3}\right)$

$m=\mathrm{-4}$ , point $\left(\mathrm{-2},\mathrm{-3}\right)$

Horizontal line containing $\left(2,\mathrm{-3}\right)$

Horizontal line containing $\left(4,\mathrm{-8}\right)$

$\left(2,6\right)$ and $\left(5,3\right)$

$\left(3,1\right)$ and $\left(2,5\right)$

$\left(4,3\right)$ and $\left(8,1\right)$

$\left(2,7\right)$ and $\left(3,8\right)$

$\left(\mathrm{-3},\mathrm{-4}\right)$ and $\left(5-2\right)$

$\left(\mathrm{-5},\mathrm{-3}\right)$ and $\left(4,\mathrm{-6}\right)$

$\left(\mathrm{-1},3\right)$ and $\left(\mathrm{-6},\mathrm{-7}\right)$

$\left(\mathrm{-2},8\right)$ and $\left(\mathrm{-4},\mathrm{-6}\right)$

$\left(6,\mathrm{-4}\right)$ and $\left(\mathrm{-2},5\right)$

$\left(3,\mathrm{-2}\right)$ and $\left(\mathrm{-4},4\right)$

$\left(0,4\right)$ and $\left(2,\mathrm{-3}\right)$

$\left(0,\mathrm{-2}\right)$ and $\left(\mathrm{-5},\mathrm{-3}\right)$

$\left(7,2\right)$ and $\left(7,\mathrm{-2}\right)$

$\left(4,2\right)$ and $\left(4,\mathrm{-3}\right)$

$\left(\mathrm{-7},\mathrm{-1}\right)$ and $\left(\mathrm{-7},\mathrm{-4}\right)$

$\left(\mathrm{-2},1\right)$ and $\left(\mathrm{-2},\mathrm{-4}\right)$

$\left(6,1\right)$ and $\left(0,1\right)$

$\left(6,2\right)$ and $\left(\mathrm{-3},2\right)$

$\left(3,\mathrm{-4}\right)$ and $\left(5,\mathrm{-4}\right)$

$\left(\mathrm{-6},\mathrm{-3}\right)$ and $\left(\mathrm{-1},\mathrm{-3}\right)$

$\left(4,3\right)$ and $\left(8,0\right)$

$\left(0,0\right)$ and $\left(1,4\right)$

$\left(\mathrm{-2},\mathrm{-3}\right)$ and $\left(\mathrm{-5},\mathrm{-6}\right)$

$\left(\mathrm{-3},0\right)$ and $\left(\mathrm{-7},\mathrm{-2}\right)$

$\left(8,\mathrm{-1}\right)$ and $\left(8,\mathrm{-5}\right)$

$\left(3,5\right)$ and $\left(\mathrm{-7},5\right)$

line $y=4x+2$ , point $\left(1,2\right)$

line $y=3x+4$ , point $\left(2,5\right)$

line $y=\mathrm{-2}x-3$ , point $\left(\mathrm{-1},3\right)$

line $y=\mathrm{-3}x-1$ , point $\left(2,\mathrm{-3}\right)$

line $3x-y=4$ , point $\left(3,1\right)$

line $2x-y=6$ , point $\left(3,0\right)$

line $4x+3y=6$ , point $\left(0,\mathrm{-3}\right)$

line $2x+3y=6$ , point $\left(0,5\right)$

line $x=\mathrm{-3}$ , point $\left(\mathrm{-2},\mathrm{-1}\right)$

line $x=\mathrm{-4}$ , point $\left(\mathrm{-3},\mathrm{-5}\right)$

line $x-2=0$ , point $\left(1,\mathrm{-2}\right)$

line $x-6=0$ , point $\left(4,\mathrm{-3}\right)$

line $y=5$ , point $\left(2,\mathrm{-2}\right)$

line $y=1$ , point $\left(3,\mathrm{-4}\right)$

line $y+2=0$ , point $\left(3,\mathrm{-3}\right)$

line $y+7=0$ , point $\left(1,\mathrm{-1}\right)$

line $y=\mathrm{-2}x+3$ , point $\left(2,2\right)$

line $y=\text{−}x+5$ , point $\left(3,3\right)$

line $y=\frac{3}{4}x-2$ , point $\left(\mathrm{-3},4\right)$

line $y=\frac{2}{3}x-4$ , point $\left(2,\mathrm{-4}\right)$

line $2x-3y=8$ , point $\left(4,\mathrm{-1}\right)$

line $4x-3y=5$ , point $\left(\mathrm{-3},2\right)$

line $2x+5y=6$ , point $\left(0,0\right)$

line $4x+5y=\mathrm{-3}$ , point $\left(0,0\right)$

line $y-3=0$ , point $\left(\mathrm{-2},\mathrm{-4}\right)$

line $y-6=0$ , point $\left(\mathrm{-5},\mathrm{-3}\right)$

line y -axis, point $\left(3,4\right)$

line y -axis, point $\left(2,1\right)$

Cholesterol. The age, $x$ , and LDL cholesterol level, $y$ , of two men are given by the points $\left(18,68\right)$ and $\left(27,122\right)$ . Find a linear equation that models the relationship between age and LDL cholesterol level.

Fuel consumption. The city mpg, $x$ , and highway mpg, $y$ , of two cars are given by the points $\left(29,40\right)$ and $\left(19,28\right)$ . Find a linear equation that models the relationship between city mpg and highway mpg.

Why are all horizontal lines parallel?

Explain in your own words why the slopes of two perpendicular lines must have opposite signs.