9.3 Add and subtract square roots  (Page 2/3)

$8\sqrt{2}-5\sqrt{2}$

$7\sqrt{2}-3\sqrt{2}$

$3\sqrt{5}+6\sqrt{5}$

$4\sqrt{5}+8\sqrt{5}$

$9\sqrt{7}-10\sqrt{7}$

$11\sqrt{7}-12\sqrt{7}$

$7\sqrt{y}+2\sqrt{y}$

$9\sqrt{n}+3\sqrt{n}$

$\sqrt{a}-4\sqrt{a}$

$\sqrt{b}-6\sqrt{b}$

$5\sqrt{c}+2\sqrt{c}$

$7\sqrt{d}+2\sqrt{d}$

$8\sqrt{a}-2\sqrt{b}$

$5\sqrt{c}-3\sqrt{d}$

$5\sqrt{m}+\sqrt{n}$

$\sqrt{n}+3\sqrt{p}$

$8\sqrt{7}+2\sqrt{7}+3\sqrt{7}$

$6\sqrt{5}+3\sqrt{5}+\sqrt{5}$

$3\sqrt{11}+2\sqrt{11}-8\sqrt{11}$

$2\sqrt{15}+5\sqrt{15}-9\sqrt{15}$

$3\sqrt{3}-8\sqrt{3}+7\sqrt{5}$

$5\sqrt{7}-8\sqrt{7}+6\sqrt{3}$

$6\sqrt{2}+2\sqrt{2}-3\sqrt{5}$

$7\sqrt{5}+\sqrt{5}-8\sqrt{10}$

$3\sqrt{2a}-4\sqrt{2a}+5\sqrt{2a}$

$\sqrt{11b}-5\sqrt{11b}+3\sqrt{11b}$

$8\sqrt{3c}+2\sqrt{3c}-9\sqrt{3c}$

$3\sqrt{5d}+8\sqrt{5d}-11\sqrt{5d}$

$5\sqrt{3ab}+\sqrt{3ab}-2\sqrt{3ab}$

$8\sqrt{11cd}+5\sqrt{11cd}-9\sqrt{11cd}$

$2\sqrt{pq}-5\sqrt{pq}+4\sqrt{pq}$

$11\sqrt{2rs}-9\sqrt{2rs}+3\sqrt{2rs}$

$\sqrt{50}+4\sqrt{2}$

$\sqrt{48}+2\sqrt{3}$

$\sqrt{80}-3\sqrt{5}$

$\sqrt{28}-4\sqrt{7}$

$\sqrt{27}-\sqrt{75}$

$\sqrt{72}-\sqrt{98}$

$\sqrt{48}+\sqrt{27}$

$\sqrt{45}+\sqrt{80}$

$2\sqrt{50}-3\sqrt{72}$

$3\sqrt{98}-\sqrt{128}$

$2\sqrt{12}+3\sqrt{48}$

$4\sqrt{75}+2\sqrt{108}$

$\frac{2}{3}\sqrt{72}+\frac{1}{5}\sqrt{50}$

$\frac{2}{5}\sqrt{75}+\frac{3}{4}\sqrt{48}$

$\frac{1}{2}\sqrt{20}-\frac{2}{3}\sqrt{45}$

$\frac{2}{3}\sqrt{54}-\frac{3}{4}\sqrt{96}$

$\frac{1}{6}\sqrt{27}-\frac{3}{8}\sqrt{48}$

$\frac{1}{8}\sqrt{32}-\frac{1}{10}\sqrt{50}$

$\frac{1}{4}\sqrt{98}-\frac{1}{3}\sqrt{128}$

$\frac{1}{3}\sqrt{24}+\frac{1}{4}\sqrt{54}$

$\sqrt{72a^5}-\sqrt{50a^5}$

$\sqrt{48b^5}-\sqrt{75b^5}$

$\sqrt{80c^7}-\sqrt{20c^7}$

$\sqrt{96d^9}-\sqrt{24d^9}$

$9\sqrt{80p^4}-6\sqrt{98p^4}$

$8\sqrt{72q^6}-3\sqrt{75q^6}$

$2\sqrt{50r^8}+4\sqrt{54r^8}$

$5\sqrt{27s^6}+2\sqrt{20s^6}$

$3\sqrt{20x^2}-4\sqrt{45x^2}+5x\sqrt{80}$

$2\sqrt{28x^2}-\sqrt{63x^2}+6x\sqrt{7}$

$3\sqrt{128y^2}+4y\sqrt{162}-8\sqrt{98y^2}$

$3\sqrt{75y^2}+8y\sqrt{48}-\sqrt{300y^2}$

$2\sqrt{8}+6\sqrt{8}-5\sqrt{8}$

$\frac{2}{3}\sqrt{27}+\frac{3}{4}\sqrt{48}$

$\sqrt{175k^4}-\sqrt{63k^4}$

$\frac{5}{6}\sqrt{162}+\frac{3}{16}\sqrt{128}$

$2\sqrt{363}-2\sqrt{300}$

$\sqrt{150}+4\sqrt{6}$

$9\sqrt{2}-8\sqrt{2}$

$5\sqrt{x}-8\sqrt{y}$

$8\sqrt{13}-4\sqrt{13}-3\sqrt{13}$

$5\sqrt{12c^4}-3\sqrt{27c^6}$

$\sqrt{80a^5}-\sqrt{45a^5}$

$\frac{3}{5}\sqrt{75}-\frac{1}{4}\sqrt{48}$

$21\sqrt{19}-2\sqrt{19}$

$\sqrt{500}+\sqrt{405}$

$\frac{5}{6}\sqrt{27}+\frac{5}{8}\sqrt{48}$

$11\sqrt{11}-10\sqrt{11}$

$\sqrt{75}-\sqrt{108}$

$2\sqrt{98}-4\sqrt{72}$

$4\sqrt{24x^2}-\sqrt{54x^2}+3x\sqrt{6}$

$8\sqrt{80y^6}-6\sqrt{48y^6}$

A decorator decides to use square tiles as an accent strip in the design of a new shower, but she wants to rotate the tiles to look like diamonds. She will use 9 large tiles that measure 8 inches on a side and 8 small tiles that measure 2 inches on a side. $9\left(8\sqrt{2}\right)+8\left(2\sqrt{2}\right)$ . Determine the width of the accent strip by simplifying the expression $9\left(8\sqrt{2}\right)+8\left(2\sqrt{2}\right)$ . (Round to the nearest tenth of an inch.)

Suzy wants to use square tiles on the border of a spa she is installing in her backyard. She will use large tiles that have area of 12 square inches, medium tiles that have area of 8 square inches, and small tiles that have area of 4 square inches. Once section of the border will require 4 large tiles, 8 medium tiles, and 10 small tiles to cover the width of the wall. Simplify the expression $4\sqrt{12}+8\sqrt{8}+10\sqrt{4}$ to determine the width of the wall.

Explain the difference between like radicals and unlike radicals. Make sure your answer makes sense for radicals containing both numbers and variables.

Explain the process for determining whether two radicals are like or unlike. Make sure your answer makes sense for radicals containing both numbers and variables.