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Evaluate 3 x 2 + 4 x + 1 when x = 3 .

40

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Evaluate 6 x 2 4 x 7 when x = 2 .

9

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Indentify and combine like terms

Algebraic expressions are made up of terms. A term is a constant, or the product of a constant and one or more variables.

Term

A term    is a constant, or the product of a constant and one or more variables.

Examples of terms are 7 , y , 5 x 2 , 9 a , and b 5 .

The constant that multiplies the variable is called the coefficient .

Coefficient

The coefficient    of a term is the constant that multiplies the variable in a term.

Think of the coefficient as the number in front of the variable. The coefficient of the term 3 x is 3. When we write x , the coefficient is 1, since x = 1 · x .

Identify the coefficient of each term: 14 y 15 x 2 a .

Solution

The coefficient of 14 y is 14.

The coefficient of 15 x 2 is 15.

The coefficient of a is 1 since a = 1 a .

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Identify the coefficient of each term: 17 x 41 b 2 z .

14 41 1

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Identify the coefficient of each term: 9 p 13 a 3 y 3 .

9 13 1

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Some terms share common traits. Look at the following 6 terms. Which ones seem to have traits in common?

5 x 7 n 2 4 3 x 9 n 2

The 7 and the 4 are both constant terms.

The 5x and the 3 x are both terms with x .

The n 2 and the 9 n 2 are both terms with n 2 .

When two terms are constants or have the same variable and exponent, we say they are like terms .

  • 7 and 4 are like terms.
  • 5 x and 3 x are like terms.
  • x 2 and 9 x 2 are like terms.

Like terms

Terms that are either constants or have the same variables raised to the same powers are called like terms    .

Identify the like terms: y 3 , 7 x 2 , 14, 23, 4 y 3 , 9 x , 5 x 2 .

Solution

y 3 and 4 y 3 are like terms because both have y 3 ; the variable and the exponent match.

7 x 2 and 5 x 2 are like terms because both have x 2 ; the variable and the exponent match.

14 and 23 are like terms because both are constants.

There is no other term like 9 x .

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Identify the like terms: 9 , 2 x 3 , y 2 , 8 x 3 , 15 , 9 y , 11 y 2 .

9 and 15, y 2 and 11 y 2 , 2 x 3 and 8 x 3

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Identify the like terms: 4 x 3 , 8 x 2 , 19, 3 x 2 , 24, 6 x 3 .

19 and 24, 8 x 2 and 3 x 2 , 4 x 3 and 6 x 3

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Adding or subtracting terms forms an expression. In the expression 2 x 2 + 3 x + 8 , from [link] , the three terms are 2 x 2 , 3 x , and 8.

Identify the terms in each expression.

  1. 9 x 2 + 7 x + 12
  2. 8 x + 3 y

Solution

The terms of 9 x 2 + 7 x + 12 are 9 x 2 , 7 x , and 12.

The terms of 8 x + 3 y are 8 x and 3 y .

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Identify the terms in the expression 4 x 2 + 5 x + 17 .

4 x 2 , 5 x , 17

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Identify the terms in the expression 5 x + 2 y .

5 x , 2 y

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If there are like terms in an expression, you can simplify the expression by combining the like terms. What do you think 4 x + 7 x + x would simplify to? If you thought 12 x , you would be right!

4 x + 7 x + x x + x + x + x + x + x + x + x + x + x + x + x 12 x

Add the coefficients and keep the same variable. It doesn’t matter what x is—if you have 4 of something and add 7 more of the same thing and then add 1 more, the result is 12 of them. For example, 4 oranges plus 7 oranges plus 1 orange is 12 oranges. We will discuss the mathematical properties behind this later.

Simplify: 4 x + 7 x + x .

Add the coefficients. 12 x

How to combine like terms

Simplify: 2 x 2 + 3 x + 7 + x 2 + 4 x + 5 .

Solution

Three lines of instructions are listed in a column on the left side of the image while four algebraic expressions are listed on the right. The first line of instruction on the left says: “Step 1. Identify like terms.” Across from step 1 in the right column is the algebraic expression: 2x squared plus 3x plus 7 plus x squared plus 4x plus 5. One line down on the right, the same algebraic expression is repeated, except each of the terms appears in one of three colors to illustrate that these are like terms: 2x squared and x squared appear as red, illustrating that these are like terms; 3x and 4x appear as blue, illustrating that these are also like terms; 7 and 5 appear as green, illustrating that these are like terms as well. The second line of instruction on the left says: “Step 2. Rearrange the expression so the like terms are together. Across from step 2 in the right column is the original algebraic expression with terms reordered so that like terms appear side by side: 2x squared plus x2, both written in red, plus 3x plus 4x, both written n blue, plus 7 plus 5, both written in green. The third line of instruction on the left says: “Step 3. Combine like terms.” Across from step 3 in the right column is the algebraic expression with like terms combined: 3x squared in red, plus 7x in blue, plus 12 in green.
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Simplify: 3 x 2 + 7 x + 9 + 7 x 2 + 9 x + 8 .

10 x 2 + 16 x + 17

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Simplify: 4 y 2 + 5 y + 2 + 8 y 2 + 4 y + 5 .

12 y 2 + 9 y + 7

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Combine like terms.

  1. Identify like terms.
  2. Rearrange the expression so like terms are together.
  3. Add or subtract the coefficients and keep the same variable for each group of like terms.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
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