4.1 Use the rectangular coordinate system  (Page 5/12)

ⓐ $\left(\mathrm{-4},2\right)$
ⓑ $\left(\mathrm{-1},\mathrm{-2}\right)$
ⓒ $\left(3,\mathrm{-5}\right)$
ⓓ $\left(\mathrm{-3},5\right)$
ⓔ $\left(\frac{5}{3},2\right)$

ⓐ $\left(\mathrm{-2},\mathrm{-3}\right)$
ⓑ $\left(3,\mathrm{-3}\right)$
ⓒ $\left(\mathrm{-4},1\right)$
ⓓ $\left(4,\mathrm{-1}\right)$
ⓔ $\left(\frac{3}{2},1\right)$

ⓐ $\left(3,\mathrm{-1}\right)$
ⓑ $\left(\mathrm{-3},1\right)$
ⓒ $\left(\mathrm{-2},2\right)$
ⓓ $\left(\mathrm{-4},\mathrm{-3}\right)$
ⓔ $\left(1,\frac{14}{5}\right)$

ⓐ $\left(\mathrm{-1},1\right)$
ⓑ $\left(\mathrm{-2},\mathrm{-1}\right)$
ⓒ $\left(2,1\right)$
ⓓ $\left(1,\mathrm{-4}\right)$
ⓔ $\left(3,\frac{7}{2}\right)$

ⓐ $\left(\mathrm{-2},0\right)$
ⓑ $\left(\mathrm{-3},0\right)$
ⓒ $\left(0,0\right)$
ⓓ $\left(0,4\right)$
ⓔ $\left(0,2\right)$

ⓐ $\left(0,1\right)$
ⓑ $\left(0,\mathrm{-4}\right)$
ⓒ $\left(\mathrm{-1},0\right)$
ⓓ $\left(0,0\right)$
ⓔ $\left(5,0\right)$

ⓐ $\left(0,0\right)$
ⓑ $\left(0,\mathrm{-3}\right)$
ⓒ $\left(\mathrm{-4},0\right)$
ⓓ $\left(1,0\right)$
ⓔ $\left(0,\mathrm{-2}\right)$

ⓐ $\left(\mathrm{-3},0\right)$
ⓑ $\left(0,5\right)$
ⓒ $\left(0,\mathrm{-2}\right)$
ⓓ $\left(2,0\right)$
ⓔ $\left(0,0\right)$

$2x+y=6$

ⓐ $\left(1,4\right)$
ⓑ $\left(3,0\right)$
ⓒ $(2,3)$

$x+3y=9$

ⓐ $\left(0,3\right)$
ⓑ $\left(6,1\right)$
ⓒ $\left(\mathrm{-3},\mathrm{-3}\right)$

$4x-2y=8$

ⓐ $\left(3,2\right)$
ⓑ $\left(1,4\right)$
ⓒ $\left(0,\mathrm{-4}\right)$

$3x-2y=12$

ⓐ $\left(4,0\right)$
ⓑ $\left(2,\mathrm{-3}\right)$
ⓒ $\left(1,6\right)$

$y=4x+3$

ⓐ $\left(4,3\right)$
ⓑ $\left(\mathrm{-1},\mathrm{-1}\right)$
ⓒ $\left(\frac{1}{2},5\right)$

$y=2x-5$

ⓐ $\left(0,\mathrm{-5}\right)$
ⓑ $\left(2,1\right)$
ⓒ $\left(\frac{1}{2},\mathrm{-4}\right)$

$y=\frac{1}{2}x-1$

ⓐ $\left(2,0\right)$
ⓑ $\left(\mathrm{-6},\mathrm{-4}\right)$
ⓒ $\left(\mathrm{-4},\mathrm{-1}\right)$

$y=\frac{1}{3}x+1$

ⓐ $\left(\mathrm{-3},0\right)$
ⓑ $\left(9,4\right)$
ⓒ $\left(\mathrm{-6},\mathrm{-1}\right)$

$y=2x-4$

$y=3x-1$

$y=\text{−}x+5$

$y=\text{−}x+2$

$y=\frac{1}{3}x+1$

$y=\frac{1}{2}x+4$

$y=-\frac{3}{2}x-2$

$y=-\frac{2}{3}x-1$

$x+3y=6$

$x+2y=8$

$2x-5y=10$

$3x-4y=12$

$y=5x-8$

$y=3x-9$

$y=\mathrm{-4}x+5$

$y=\mathrm{-2}x+7$

$x+y=8$

$x+y=6$

$x+y=\mathrm{-2}$

$x+y=\mathrm{-1}$

$3x+y=5$

$2x+y=3$

$4x-y=8$

$5x-y=10$

$2x+4y=8$

$3x+2y=6$

$5x-2y=10$

$4x-3y=12$

Weight of a baby. Mackenzie recorded her baby’s weight every two months. The baby’s age, in months, and weight, in pounds, are listed in the table below, and shown as an ordered pair in the third column.

ⓐ Plot the points on a coordinate plane.

ⓑ Why is only Quadrant I needed?

Weight of a child. Latresha recorded her son’s height and weight every year. His height, in inches, and weight, in pounds, are listed in the table below, and shown as an ordered pair in the third column.

ⓐ Plot the points on a coordinate plane.

ⓑ Why is only Quadrant I needed?

Explain in words how you plot the point $\left(4,\mathrm{-2}\right)$ in a rectangular coordinate system.

How do you determine if an ordered pair is a solution to a given equation?

Is the point $\left(\mathrm{-3},0\right)$ on the x -axis or y -axis? How do you know?

Is the point $\left(0,8\right)$ on the x -axis or y -axis? How do you know?