4.1 Use the rectangular coordinate system  (Page 2/12)

Solution

1. ⓐ Since $x=0$ , the point whose coordinates are $(0,5)$ is on the y -axis.
2. ⓑ Since $y=0$ , the point whose coordinates are $\left(4,0\right)$ is on the x -axis.
3. ⓒ Since $y=0$ , the point whose coordinates are $(\mathrm{-3},0)$ is on the x -axis.
4. ⓓ Since $x=0$ and $y=0$ , the point whose coordinates are $(0,0)$ is the origin.
5. ⓔ Since $x=0$ , the point whose coordinates are $(0,\mathrm{-1})$ is on the y -axis.
   

Solution

Point A is above $\mathrm{-3}$ on the x -axis, so the x -coordinate of the point is $\mathrm{-3}$ .

• The point is to the left of 3 on the y -axis, so the y -coordinate of the point is 3.
• The coordinates of the point are $(\mathrm{-3},3)$ .

Point B is below $\mathrm{-1}$ on the x -axis, so the x -coordinate of the point is $\mathrm{-1}$ .

• The point is to the left of $\mathrm{-3}$ on the y -axis, so the y -coordinate of the point is $\mathrm{-3}$ .
• The coordinates of the point are $(\mathrm{-1},\mathrm{-3})$ .

Point C is above 2 on the x -axis, so the x -coordinate of the point is 2.

• The point is to the right of 4 on the y -axis, so the y -coordinate of the point is 4.
• The coordinates of the point are $(2,4)$ .

Point D is below 4 on the x -axis, so the x -coordinate of the point is 4.

• The point is to the right of $\mathrm{-4}$ on the y -axis, so the y -coordinate of the point is $\mathrm{-4}.$
• The coordinates of the point are $(4,\mathrm{-4})$ .

Point E is on the y -axis at $y=\mathrm{-2}$ . The coordinates of point E are $\left(0,\mathrm{-2}\right).$

Point F is on the x -axis at $x=3$ . The coordinates of point F are $\left(3,0\right).$